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nlexa [21]
3 years ago
7

Please help! Math problem.2x+4=0: Solve for x

Mathematics
2 answers:
Irina-Kira [14]3 years ago
6 0

Equation: 2x+4=0

Subtract 4 from both sides:

2x+4-4=0-4\\2x=-4

Divide both sides by 2:

\frac{2x}{2}=\frac{-4}{2}

Simplify:

\frac{-4}{2}=-2\\x=-2

Therefore, your answer would be x = -2.

-TestedHyperr

lutik1710 [3]3 years ago
4 0

Answer:

x = -2

Step-by-step explanation:

2x + 4 = 0

2x= -4

x=-2

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Identify which Quadratic Form this Function is in.<br> y = 4(x + 2) (x - 6)
Gala2k [10]

It is an upward quadratic function

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3 0
3 years ago
(8+2)-5=???????????????????
sasho [114]

Answer:

<h2>5</h2>

Step-by-step explanation:

<h2>8+2 -5</h2><h2>8+2=10 - 5 </h2><h2>10 -5 = 5 </h2>

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5 0
3 years ago
Read 2 more answers
Omg please help me. ​
Leya [2.2K]

Answer:

y=9.75x+60

Step-by-step explanation:

We want our equation to look like y=mx+b

Let's start out by calculating the slope

\frac{118.5-89.25}{6-3}=9.75

we have

y=9.75x+b

we know that when x= 3 y= 89.25

89.25=9.75(3)+b

solve for b = 60

6 0
2 years ago
Can someone help me with this. Will Mark brainliest. Need answer and explaination/work. Thank you!
Lesechka [4]
The mid point would be (1,25.5)
3 0
2 years ago
In 2001 the mint indoor pool vault record was 20 and 1/6 the women’s record for the indoor pool vault was 15 and 5/12 FT what is
blondinia [14]

Answer:

35 and 7/12 feet is the combined height of the two records.

Step-by-step explanation:

Height of the indoor pool vault record for men = 20 and 1/6 ft =\frac{121}{6} ft

Height of indoor pool vault record for women = 15and 5/12 ft =\frac{185}{12} ft

The combined height of the two records :

\frac{121}{6} ft+\frac{185}{12} ft

\frac{121\times 2}{6\times 2} ft+\frac{185}{12} ft

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\frac{242+185}{12} ft=\frac{427}{12}=35\frac{7}{12}

35 and 7/12 feet is the combined height of the two records.

5 0
3 years ago
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