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3 years ago

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Does anyone know the answer ?

1 answer:

LenKa [72]3 years ago

3 0

Answer:

i think its inches per foot b/c it says what where the final units for this conversion i hope this is helpful.

Step-by-step explanation:

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I'm not sure how to start. Can anyone help with a few letters? Once I get a start, I can finish

maks197457 [2]

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4 0

3 years ago

Read 2 more answers

a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues

DerKrebs [107]

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that $P(0) = 24000$

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

$P(t) = P(0)(1+r)^{t}$

$29000 = 24000(1+r)^{20}$

$(1+r)^{20} = \frac{29000}{24000}$

$\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}$

$1 + r = 1.0095$

So

$P(t) = P(0)(1+r)^{t}$

$P(t) = 24000(1.0095)^{t}$

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

$P(t) = 24000(1.0095)^{t}$

$P(100) = 24000(1.0095)^{100} = 61779$

It will have a population of 61,779 in 2000.

4 0

3 years ago

The tallest man living in is Sultan Kosen from Turkey. He measures 251 cm. How many meters tall is he?

sammy [17]

Answer:

2.51 m

Step-by-step explanation:

100 cm = 1 m

(251 cm) / (100 cm) = 2.51 m

3 0

3 years ago

Read 2 more answers

Fraction help please<br> K

dexar [7]

What’s the question??

3 0

3 years ago

Given the function g(x)=x^2+2x-5g(x)=x

dimaraw [331]

We have been given a function $g(x)=x^2+2x-5$ . We are asked to find average rate of change of the function over the interval $-6\leq x\leq 1$ .

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

For our given function $b=1$ and $a=-6$ .

$\text{Average rate of change}=\frac{g(1)-g(-6)}{1-(-6)}$

$g(1)=1^2+2(1)-5$

$g(1)=1+2-5$

$g(1)=-2$

$g(-6)=(-6)^2+2(-6)-5$

$g(-6)=36-12-5$

$g(-6)=19$

$\text{Average rate of change}=\frac{-2-19}{1+6}$

$\text{Average rate of change}=\frac{-21}{7}$

$\text{Average rate of change}=-3$

Therefore, the average rate of change of the function is $-3$ over the interval $-6\leq x\leq 1$ .

4 0

3 years ago