Answer:
The sample size will be "
". A further explanation is given below.
Step-by-step explanation:
Let the sample size will be:
= n
The given values are:
Standard deviation,
= 1.4
ME,
= 0.3
As we know,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
<span>If you would like to
know how many of each did Jan buy, you can calculate this
using the following two equations:
b ... the number of books
m ... the number of magazines
$16 = b * $3 + m * $2.50 ... 16 = 3 * b + 2.50 * m
b + m = 6 ... b = 6 - m
__________________
</span>16 = 3 * b + 2.50 * m
<span>16 = 3 * (6 - m) + 2.50 * m</span>
16 = 3 * 6 - 3 * m + 2.50 * m
16 - 18 = - 3 * m + 2.50 * m
- 2 = - 0.50 * m /0.50
m = 2 / 0.50
m = 4 magazines
<span>b = 6 - m = 6 - 4 = 2 books</span>
Result: Jan bought 4 magazines and 2 books.
There are 50% chance's that it would land on heads or tails. there could be many different outcomes like (H) for heads and (T) for tails many times like this H, T, H, T, H, T.
The answer is 18
Working out:
1 1/2 x 4 =6
6 x 3=18
