<em><u>Question:</u></em>
The difference of two numbers is nine if the larger number is one more than twice the smaller number find a larger number
<em><u>Answer:</u></em>
<em><u>The larger number is 17</u></em>
<em><u>Solution:</u></em>
Let the smaller number be "a"
Let the larger number be "b"
The difference of two numbers is nine
Therefore,
b - a = 9 ------ eqn 1
larger number is one more than twice the smaller number
Therefore,
b = 1 + 2a ----- eqn 2
Substitute eqn 2 in eqn 1
1 + 2a - a = 9
<h3>a = 8</h3>
Substitute a = 8 in eqn 1
b - 8 = 9
b = 9 + 8
<h3>b = 17</h3>
Thus the larger number is 17
Answer:
x>6
Step-by-step explanation:
Then you'll need to get started on it pretty soon.
Just take it slow and easy, and remember your order of operations (or PEMDAS).
First look through it and do any multiplications and divisions that you find.
Then do the additions and subtractions.
I just gave it a quick scan and I came up with 26. I dont know if it's correct.
Get to work. You can do this !
It's neither.
If it were to be an improper fraction, it would be something like 3/2 instead of 2/3.
If it were to be a mixed number, it would look like 1 1/3.
By AAS congruency the two triangles are congruent
