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Natali5045456 [20]
3 years ago
5

Hellllllllllllllllllllppppppppppppppppppppp

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

Y-intercept: (0, -10)

X-intercepts: (5,0), (1,0)

Axis of symmetry: (3,0)

Step-by-step explanation:

You can tell what the y-intercept is by looking at the function. At the end there is a “-10”, which indicates that it’s the y-intercept.

There are many ways to find x-intercepts. You can factor the function, use the quadratic formula, or complete the square.

By factoring it, you get

-2(x-5)(x-1)=0

If one part of it equals zero, than the whole function equals zero.

So it can be split up like this

(x-5)=0

(x-1)=0

So...

x=5 and x=1 are the the zeros or (5,0) and (1,0)

Finally, you convert the function from standard form to vertex form. By doing -b/2a, you can find the x-coordinate of the vertex, which is the axis of symmetry. The answer is 3 or (3,0) because -12/2(-2)= 3.

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Answer:

C) 2400

Step-by-step explanation:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

Computers = 10

Printers = 3

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3 years ago
Explain why you should récord a 1 in the tens columna when you regroup in addition problem
ser-zykov [4K]
You should write a 1 because I f what you add is 11, 12, 13, 14, 15, 16, 17, 18, or 19 there is a 1 in the front of the numbers so you must put a 1 but if the number was 76 the number in the front is 7 so you would put 7 on the tens column.

8 0
3 years ago
A t-shirt increased in price by
AVprozaik [17]

Step-by-step explanation:

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=20.24

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5 0
3 years ago
A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
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