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2 years ago

What’s the missing angle. Brainliest if your correct

Mathematics

1 answer:

stellarik [79]2 years ago

6 0

We are given:

We know that the sum of all interior angles of a Pentagon is 540°

we are given 4 out of the 5 angles

Solving for x:

since the sum of all 5 angles is 540°:

75 + 130 + 135 + x + 90 = 540

x + 430 = 540

x = 540 - 430

x = 110°

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412.638 in expanded form

ser-zykov [4K]

(4x100)+(1x10)+(2x1)+(6x1/10)+(3x1/100)+(8x1/1000)

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3 years ago

Read 2 more answers

What is 93.65 in word form?

Marrrta [24]

Ninty three point six five I think

7 0

3 years ago

The population of a town can be modeled by P= 22,000 + 125t, where P represents the population and the t represents the number o

nlexa [21]

Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032

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3 years ago

I(1, 1) and J (-3,-3) Find the midpoint of the line segment

Pavlova-9 [17]

The Answer is (-1,-1)

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3 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

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2 years ago