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gtnhenbr [62]
3 years ago
14

write two addition sentences where the sum is positive. in each sentence, one addend should be positive and the other negative

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0
10 + (-5) = 10 - 5 = 5

-11 + 20 = 20 + (-11) = 20 - 11 = 9

102 + (-1) = 102 - 1 = 101

-20 + 60 = 60 + (-20) = 60 - 20 = 40
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Evaluate 7y - 2<br> when y = 9
kotykmax [81]

Answer:

The answer is 61.

Step-by-step explanation:

7(9)-2

63-2

61

5 0
3 years ago
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Does the method of quadratic equations apply for all equations?​
zheka24 [161]

Answer:

i don't think so that's why it's for quadratic and not others like linear or geometric, I might be wrong thiugh

6 0
3 years ago
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Please help!!!!
nlexa [21]

Answer:

225

Step-by-step explanation:

Using the basic components of summation ∑

∑n = \frac{1}{2} n(n + 1) and ∑1 = n

Thus

∑ (2n - 1) ← for n = 1 to 15

= ∑2n - ∑1

= 2∑n - ∑1

= 2 (\frac{1}{2} n(n + 1)) - n

= n(n + 1) - n ← Evaluate for n = 15 ( the upper value )

= 15 × 16 - 15

= 240 - 15

= 225

3 0
3 years ago
I rlly need some help please if ur big brains im going to be asking multiple questions right now
Lynna [10]

You can break the shape up into a rectangle and a right triangle.

Use your trig ratios to find the missing sides.

Add all the sides up and you have your perimeter!

//

p = 2(l) + 2(w)

p = 2(10)  + 2(4)

p = 28

//

tan =  \frac{opp}{adj}

\tan(45) =  \frac{10}{adj}

adj =  \frac{10}{ \tan(45) }

adj = 10

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{10}^{2}  + 10 {}^{2}  =  {200}^{2}

\sqrt{200} = 14.14213562

//

p = 10 + 4 + (4 + 10) + 14.14213562

<em>*notice how one of the 10 is left out because it is inside the shape so we can't use that to find perimeter.</em>

p = 42.14

3 0
3 years ago
System of equations have one solution<br> A always<br> B sometimes<br> C never
77julia77 [94]
C never, there are always different methods to solve a problem but don't forget that the equation always stays the same!
6 0
3 years ago
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