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Natalka [10]
2 years ago
8

Adding and subtracting functions g(x) = 2x f (x) = −2x^3 + 2x Find g(x) + f (x)​

Mathematics
1 answer:
Andrei [34K]2 years ago
5 0

Answer:

-2x³+4x

Step-by-step explanation:

g(x) + f(x)

(2x) + (-2x³+2x)

-2x³+4x

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Type the expression that results from the following series of steps:
swat32

Answer:

<em>start with y</em>

y

<em>add 7</em>

y+7

<em>multiply by 3</em>

3(y+7)

<em>subtract 6</em>

3(y+7)-6

<u>therefore the answer is:</u>

3y + 21 - 6

=

3y + 15 or 3(y+5)

5 0
2 years ago
I really need help, this is probability and statistics, if anyone else is taking this class, please help, it is a unit test stud
Vikki [24]

Answer:

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Step-by-step explanation:

i hope this helps you!

3 0
2 years ago
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You estimate the distance from your house to your school to be 1.6 miles. The actual distance is 1.9 miles. Find the percent err
Bezzdna [24]
To find percent error you use the following formula:
% Error =  \frac{final value - given value}{given value}
% error = (1.6 - 1.9)/1.9 * 100% = 15.79%
5 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
Please help. Evaluate 5(n+3)-7n , when n = 6
never [62]

Answer:

3

Step-by-step explanation:

because if N = 6, then you will have to substitute the n to n and then do the order of operation. first it will be 6+3=9 and then 9*5=45. then you will do 7*6=42 and then subtract 45-42=3

5 0
2 years ago
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