Recall that the formula for the perimeter of a rectangle is: 2Length+2Width
With this in mind, we have that the original design is 96×60, where 90 is length and 60 is width, so it would simply be:
2(96+l) + 2 (60+w) = New Perimeter
Or simplified, it'd be:
2l + 2w + 312 = New Perimeter
100, because, x^2 - 20x + 100 = ( x - 10 )^2;
Answer:
3:30PM
Step-by-step explanation:
Martina starting playing video games as soon as she got home from school. She played video games for 15 minutes. Then Martina helped clean the kitchen for 45 minutes. After the kitchen was clean, it took Martina 15 minutes to finish her homework. When Martina finished her homework, it was 4:45 P.M. What time did Martina get home from school?
Step 1
We add up the minutes it took her to do things
= Minutes for video games + Minutes for cleaning the kitchen + Minutes for doing homework
= 15 minutes + 45 minutes + 15 minutes
= 75 minutes
= 1 hour 15 minutes
Step 2
When Martina finished her homework, it was 4:45 P.M. What time did Martina get home from school?
This is calculated be subtracting 1 hour 15 minutes from 4:45 PM
= 4:45 PM - 1 : 15
= 3:30PM
Therefore, Martha got home from school by 3:30 PM
Answer: The graph is attached.
Step-by-step explanation: The given functions whose graphs are to be compared are as follows:
In the attached figure, the graphs of both (A) and (B) are shown. We can easily see see from there, the shapes of both the graphs are same.
But, at x = 0, y = ∞ and at x = ∞, y = 0 in graph (A).
At x = 0, y = ∞ and at x = ∞, y = 6 in graph (B).
Thus, the comparison can be seen in the figure very clearly.
Answer:
Step-by-step explanation:
First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items
F(x) = x^3-3x^2+0x+0
We have to divide this by x-2
Leading terms in the dividend and divisor are
x^3 and x
Hence quotient I term would be x^3/x=x^2
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
Multiply x-2 by x square and write below the term and subtract
We get
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
---------------
-x^2+0x
Again take the leading terms and find quotient is –x
x-2) x^3-3x^2+0x+0(x^2-x
x^3-2x^2
---------------
-x^2+0x
-x^2-2x
Subtract to get 2x +0 as remainder.
x-2) x^3-3x^2+0x+0(x^2-x-2
x^3-2x^2
---------------
-x^2+0x
-x^2+2x
-------------
-2x-0
-2x+4
------------------
-4
Thus remainder is -4 and quotient is x^2-x-2
