Answer:
The x-coordinate is \dfrac{\pi}{6}[/tex].
Step-by-step explanation:
We are given a function f(x) as:

Now on differentiating both side with respect to x we get that:

When 
this means that 
Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval
.
also we know that
----(1) (which lie in the second quadrant)
so on comparing our equation with equation (1) we obtain:

Hence, the x-coordinates where
for
is
.
For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)
Answer:
59
Step-by-step explanation:
b^3 is 27
2(27) is 54
54+5 is 59
if u mean (2b)^3 then 2b is 6
6^3 is 216
plus 5 is 221