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andreev551 [17]
3 years ago
9

2 K + Cl2 → 2 KCI How many grams of KCI (74.55 g/mol) is produced from 2.50 mol of K?

Chemistry
1 answer:
Rudik [331]3 years ago
8 0

Answer:  186.3 g of KCl will be produced from 2.50 mol of K

Explanation:

The balanced chemical reaction is:

2K+Cl_2\rightarrow 2KCl  

According to stoichiometry :

2 moles of K produce = 2 moles of KCl

Thus 2.50 moles of K will produce=\frac{2}{2}\times 2.50=2.50moles  of KCl

Mass of KCl=moles\times {\text {Molar mass}}=2.50moles\times 74.55g/mol=186.3g

Thus 186.3 g of KCl will be produced from 2.50 mol of K

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The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
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Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

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The initial condition is A(0)= A₀,

\therefore A_0=Ce^{0.k}

\Rightarrow C=A_0

\therefore A=A_0e^{kt}.........(1)

Given that the Pb_{209}  has half life of 3.3 hours.

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\frac12A_0=A_0e^{k\times3.3}

\Rightarrow ln(\frac12)= 3.3k     [taking ln both sides, ln \ e^a=a]

\Rightarrow k=\frac{ln \frac12}{3.3}

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

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Now putting the value of k,A and A₀in the equation (1)

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\Rightarrow t= \frac{ln (0.2)}{-0.21}

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

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