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n200080 [17]
2 years ago
14

Which of the following will form a metallic bond with a metal?

Chemistry
1 answer:
lisabon 2012 [21]2 years ago
4 0
It’s really any metal because metals form metallic bonds. They are the only substances which can make metallic bonds. So the answer is A
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(1) Complete the word equation for the complete combustion of methane in
Deffense [45]

Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.

6 0
2 years ago
Calcium is a nontoxic metal that is used in supplements to maintain strong bones. Under high pressure conditions, over about 320
Lera25 [3.4K]

Explanation:

It is known that in a simple cubic unit cell the atoms are only present at the corner of the unit cell. This means that there are in total 8 atoms present in a simple cubic unit cell.

Therefore, in one simple cubic unit cell sharing of one atom is only \frac{1}{8}.

Hence, the total number of atoms in a unit cell will be as follows.

            8 \times \frac{1}{8} = 1

Thus, we can conclude that there is 1 calcium atom present in each unit cell.

4 0
3 years ago
You collect a sample of gases from an indoor pool area. The sample contains air and water vapor. The total pressure is 100.18 ki
Nikolay [14]

C. 96.82 kPa because to find the amount of pressure the air is causing you need to subtract the amount of pressure the water vapor is causing because the only two gasses making up the air in the pool area are air and water vapor.

8 0
3 years ago
Read 2 more answers
Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C
ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O  (1)  

The enthalpy of reaction (1) is given by:

\Delta H = \Delta H_{r} - \Delta H_{p}   (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

  • 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
  • 7O₂: 7 moles of 1 O=O bond  
  • 4CO₂: 4 moles of 2 C=O bonds  
  • 6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

\Delta H = \Delta H_{r} - \Delta H_{p}

\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})      

\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})  

\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol  

\Delta H = -2860 kJ/mol          

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

Read more here:

brainly.com/question/11753370?referrer=searchResults  

I hope it helps you!        

7 0
2 years ago
What law states that the volume of a gas is proportional to the miles of the gas when pressure and temperature are kept constant
Rufina [12.5K]

ideal gas law. but you are talking about moles of gas not miles

5 0
2 years ago
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