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alina1380 [7]
3 years ago
5

Consider the following combustion reaction:

Chemistry
2 answers:
borishaifa [10]3 years ago
8 0

Answer: 0.34827 mole CO2.

Explanation: Solved in the attached picture.

ZanzabumX [31]3 years ago
6 0

Answer:

vxcvggccbbcCbnmhxx vgfscvjjg

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In order to calculate the mass of an element in a given mass of a compound the mass of the compound is multiplied by the mass
Allushta [10]
Molar mass is the mass of a given substance divided by the amount of that substance, measured in g/mol.
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3 years ago
How many electrons will each element gain or lose in forming an ion?
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8 0
3 years ago
3) 2500 pounds to Kilograms<br><br> Would this be 1,250?
Softa [21]

Answer:

1134

Explanation:

(the ones place was rounded up). 1133.981 is the unrounded answer.

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3 years ago
Why is genotype not the only factor that affects phenotype?
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7 0
3 years ago
If 28 ml of 5.8 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?
ipn [44]

First we have to refer to the reaction between the acid and the base: <span>

H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4 

From this balanced equation we can see that for every 1 mol of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml of 5.8 M acid, we need to find out how many mols of acid that is: 

<span>28mL * (1L/1000mL) * 5.8 mol/L =  0.1624 mol H2SO4</span></span>

<span>
Since we need 2 mol of base per mol of acid, we need:</span>

<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>

MolarMass of NaHCO3 is 84.01 g/mol 

<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>

3 0
3 years ago
Read 2 more answers
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