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3 years ago

Please help me please

Mathematics

2 answers:

tia_tia [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Mazyrski [523]3 years ago

5 0

Answer:

Step-by-step explanation:

Did I get the other question right and did you see the comment

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the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we

baherus [9]

0.4 lbs each.

<h3>Further explanation</h3>

Given: 

The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
The weight of the bag of sugar is 1.4 Ib

Question: 

What is the weight of each piece of butter?

The Process: 

The two steps for obtaining the weight of each piece of butter are as follows:

Step-1: the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

$\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }$

Step-2: the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

$\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Let's also consider the following quick steps.

Quick steps:

$\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>

What is the cost of the toy car? brainly.com/question/5282516
How much netting did Mrs.Nguyen use per goal? brainly.com/question/13174287
How much punch is in each bowl? brainly.com/question/1878521

Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

5 0

2 years ago

Read 2 more answers

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

4 0

3 years ago

Solve for x.

White raven [17]

Step-by-step explanation:

$25(x - 910) = - 234 \\ 25x - 22750 = - 234 \\ 25x = 22516 \\ x = \frac{22516}{25} \\ x = 900 \frac{16}{25}$

4 0

2 years ago

4 cot theta = tan theta how do I I find the value of quadrant?

Ray Of Light [21]

Answer:

4cotα=tanα

4(1/tanα)=tanα

(4/tanα)=tanα

cross multiply

=> 4=tan²α

√4=√tan²α

±2=tanα

α=arc( tan) |2|

α=63.4° ( in first quadrant)

and

α=180+63.4=243.4 in the third quadrant

since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)

α=180–63.4=116.6° in the second quadrant

α=360–63.4=296.6 in the fourth quadrant

therefore theta( in my case, alpha) lies in all four quadrants and is equal to:

α=63.4°,243.4°,116.6°and 296.6°

5 0

3 years ago

A quadrilateral has vertices at A(-5,5), B(1,8), C(4,2), and D(-2,-2). Use slope to determine if the quadrilateral is a rectangl

AysviL [449]

Answer:

The quadrilateral is not a rectangle

Step-by-step explanation:

we know that

If a quadrilateral ABCD is a rectangle

then

Opposite sides are congruent and parallel and adjacent sides are perpendicular

Remember that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

A(-5,5), B(1,8), C(4,2), and D(-2,-2)

Plot the figure to better understand the problem

see the attached figure

Find the slope of the four sides and then compare

step 1

Find slope AB

A(-5,5), B(1,8)

substitute in the formula

$m=\frac{8-5}{1+5}$

$m=\frac{3}{6}$

$m_A_B=\frac{1}{2}$

step 2

Find slope BC

B(1,8), C(4,2)

substitute in the formula

$m=\frac{2-8}{4-1}$

$m=\frac{-6}{3}$

$m_B_C=-2$

step 3

Find slope CD

C(4,2), and D(-2,-2)

substitute in the formula

$m=\frac{-2-2}{-2-4}$

$m=\frac{-4}{-6}$

$m_C_D=\frac{2}{3}$

step 4

Find slope AD

A(-5,5), D(-2,-2)

substitute in the formula

$m=\frac{-2-5}{-2+5}$

$m=\frac{-7}{3}$

$m_A_D=-\frac{7}{3}$

step 5

Verify if the opposites are parallel

Remember that

If two lines are parallel, then their slopes are the same

The opposite sides are

AB and CD

BC and AD

we have

$m_A_B=\frac{1}{2}$

$m_C_D=\frac{2}{3}$

$m_A_B \neq m_C_D$

It is not necessary to continue verifying, because two of the opposite sides are not parallel

therefore

The quadrilateral is not a rectangle

4 0

3 years ago