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Aloiza [94]
3 years ago
11

Please help me please

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

F

Step-by-step explanation:

Mazyrski [523]3 years ago
5 0

Answer:

H

Step-by-step explanation:

Did I get the other question right and did you see the comment

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2 years ago
. The sandwich shop offers 8 different sandwiches. Jamey likes them all equally. He picks one randomly each day for lunch. Durin
Margarita [4]

Answer:

Step-by-step explanation:

From the given information:

A sandwich shop offers eight types of sandwiches, and Jamey likes all of them equally.

The probability that Jamey picks any one of them is 1/8

Suppose

X represents the number of times he chooses salami

Y represents the number of times he chooses falafel

Z represents the number of times he chooses veggie

Then  X+Y+Z ≤ 5 and;

5-X-Y-Z represents the no. of time he chooses the remaining

8 - 3 = 5 sandwiches

However, the objective is to determine the P[X=x,Y=y,Z=z] such that 0≤x,y,z≤5

So, since he chooses x no. of salami sandwiches with probability (1/8)x

and y number of falafel with probability (1/8)y

and for z (1/8)z

Therefore, the remaining sandwiches are chosen with probability \dfrac{5}{8} (5-x-y-z)

So. these x days, y days and z days can be arranged within five days in

= \dfrac{5!}{x!y!z!(5-x-y-z)!}

Thus;

P[X=x,Y=y,Z=z]=  \dfrac{5!}{x!y!z!(5-x-y-z)}  \times \dfrac{1}{8}x*\dfrac{1}{8}y* \dfrac{1}{8}z* \dfrac{5}{8}(5-x-y-z)

since 0 ≤ x, y, z ≤ 5 and x + y + z ≤ 5.

The distribution is said to be Multinomial distribution.

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3 years ago
(1/4)^3+(3/4)^3+3(1/4)(3/4)(1/4+3/4)
bogdanovich [222]
The answer should be 1
6 0
3 years ago
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