3 years ago

Im confused on how to solve this.

1 answer:

3 0

The teacher threw you a circle and said “solve”. But seriously though, is there A statement above? Or if not then “ACB” would be 30 degrees.

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

If alpha beta are the roots of the equation

Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

$ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }$

Thank you

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