The standard plate count (SPC) method involves diluting 1.0m of bacterial culture into a series of water blanks, and then taking a sample from the water blanks to add to empty petri plates which will be filled with melted agar.
The standard plate count is a method used in microbiology, which is used to gain an insight to estimate the density of bacterial population which is present in a bacterial culture broth. This is done by plating a small concentration of the culture in a petri-dish and then counting the colonies which form in the petri-plate. This method is used mostly in the food industry, to find the density of mesophilic bacteria in food. This method is extremely essential to determine the primary source of the bacterial contaminant.
Learn more about standard plate count here-
brainly.com/question/14803589
#SPJ4
The statement which best explains why Pepsin will not break down starch is that enzymes only work for specific substrates.
<h3>
What is an Enzyme?</h3>
This is referred to as a biological catalyst which helps to speed the rate of chemical reaction in the body by lowering the activation energy needed to start it up. it is also proteinous and can be denatured by heat and other substance such as chemicals.
They are also substrate specific which means they can't act on any type of substance. For example enzyme such as amylase acts on only starch while pepsin acts on only protein.
Read more about Enzyme here brainly.com/question/1596855
#SPJ1
brainly.com/question/28215908
<span>the answer would be animals can produce and have fertile offspring </span>
<span />
The garden plants and snails stay balanced as they are still being eaten. However, if the cat is removed, the birds will overpopulate and then the snail would be eaten and decrease faster which gives garden plants an increase in population due to the decrease in snails. Hope this helps!
Answer:
12 : 3 : 1
Explanation:
According to Mendel's principles, a dihybrid cross between two heterozygous summer squash parents (WwGg X WwGg) should yield offsprings, 12 with white, 3 with yellow and 1 with green color phenotype. The classic Mendelian phenotypic ratio for dihybrid cross is 9:3:3:1. In this case, genotypes W- G- and W- gg produce white color phenotype. This is because we have 12: 3: 1 phenotypic ratio in which the alleles of two different genes assort independently into gametes.
<em>Dihybrid cross for heterozygous summer squash:</em>
WG Wg wG wg
WG WWGG WWGg WwGG WwGg
Wg WWGg WWgg WwGg Wwgg
wG WwGG WwGg wwGG wwGg
wg WwGg Wwgg wwGg wwgg
Genotypes:
W-G- and W- gg = white = 12
ww G- = yellow = 3
ww gg = green = 1