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Artist 52 [7]
3 years ago
5

A wallpaper design uses 15 parallelogram-shaped pieces of paper,each with a bas of 3 inches and a height of 2 icnhes.How much pa

per is used to make 15 pieces?
Mathematics
1 answer:
ki77a [65]3 years ago
7 0
To answer this you will use the formula for finding area of a parallelogram.

A = bh
3 inches x 2 inches
A = 6 square inches per piece of paper

6 square inches x 15 = 90 square inches

90 in.² of paper is used to make 15 pieces.
You might be interested in
Which correctly describes a cross section of the cube below? Check all that apply.
dmitriy555 [2]

Answer:

A cross section parallel to the base is a square measuring 4 cm by 4 cm.

A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

Step-by-step explanation:

Cross sections parallel and Perpendicular to the base are squares 4 × 4

The diagonal cross section will be a rectangle with base 4 and height

sqrt(4² + 4²) = 4sqrt(2) > 4

7 0
3 years ago
Read 2 more answers
A ball is shot into the air using a brand new super-high-tech robotic arm to help baseball players practice catch fly balls.
stepladder [879]

Answer:

69 feet

Step-by-step explanation:

we have

h(t)=-16t^{2}+64t+5

where

h(t) is the height of the ball

t is the time in seconds

we know that the given equation is a vertical parabola open downward

The vertex is the maximum

so

the y-coordinate of the vertex represent the maximum height of the ball

Convert the quadratic equation into vertex form

The equation in vertex form is equal to

y=(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

h(t)=-16t^{2}+64t+5

h(t)-5=-16t^{2}+64t

h(t)-5=-16(t^{2}-4t)

h(t)-5-64=-16(t^{2}-4t+4)

h(t)-69=-16(t^{2}-4t+4)

h(t)-69=-16(t-2)^{2}

h(t)=-16(t-2)^{2}+69

the vertex is the point (2,69)

therefore

The maximum height is 69 ft

6 0
3 years ago
A bag of chocolate mix weighed 1/4 of a kilogram could make enough brownies to feed 1/7 of the students at school how many bags
Hoochie [10]
A "whole" will be 7/7, or just 1 whole.

so we know one bag can do 1/7 of all students, how many will it be needed to do 7/7?

well, in 7/7 there are seven 7/7, so, 7 bags then, or one could say,

\bf \begin{array}{ccll}
\stackrel{chocolate}{bag}&\stackrel{fraction}{students}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&\frac{1}{7}\\\\
x&\frac{7}{7}
\end{array}\implies \cfrac{1}{x}=\cfrac{\quad \frac{1}{7}\quad }{\frac{7}{7}}\implies \cfrac{1}{x}=\cfrac{1}{7}\cdot \cfrac{7}{7}
\\\\\\
\cfrac{1}{x}=\cfrac{1}{7}\implies 7=x
5 0
3 years ago
Solve the following equation for x using the natural logarithm
labwork [276]
Use log rule
log(ab) = log a + log b

Take log of both sides:
ln 4 + ln 4^x = ln 10 + ln e^{-x}

Use log rule
log(a^n) = n*log(a)

ln 4 + xln 4 = ln 10 -xln e \\  \\ ln 4 + xln 4 = ln 10 -x \\  \\ x ln 4+x = ln 10 - ln 4 \\  \\ x(ln 4 +1) = ln 10 -ln 4 \\  \\ x = \frac{ln 10 - ln 4}{ln 4 +1}
5 0
3 years ago
Which shapes can the composite figure be divided into to find the area?
GrogVix [38]
A rectangle and two triangles
3 0
3 years ago
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