What is 897 divided 7960

Zarrin [17]

Answer:

Concept: Mathematics

When you multiply a number by something to the 10 power of something then you move whatever place of the exponential to the right if its positive and left if it's negative.

1.365 × 10^1
You see its positive 1 hence we move one space to the right
Our answer is now 13.65

You keep doing the same thing

1.365 × 10^2
136.5

Lastly

1.365 ×10^3
1365

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4 0

3 years ago

Can somebody help me with Find 15% of $25

Zolol [24]

Answer:

$3.75

Step-by-step explanation:

This is the answer! Just trust me!

7 0

3 years ago

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20 POINTS! PLS HELP!

Arturiano [62]

First statement is correct. If Sasha reads her novel for 94 minutes, she meets the minimum reading requirement without reading any of the autobiography.

Given,

The rate of reading of a novel by Sasha = 0.8 pages per minute

The rate of reading of autobiography by Sasha = 0.5 pages per minute

The reading requirement of Sasha's English class = atleast 75 pages per week

The given equation: 0.8n + 0.5a ≥ 75

n is the number of minutes she reads the novel

a is the number of minutes she reads the autobiography

Now, let's check the statements:

Statement 1: If Sasha reads her novel for 94 minutes, she meets the minimum reading requirement without reading any of the autobiography.

That is,

0.8 × 94 + 0.5 × 0 ≥ 75

75.2 ≥ 75

This statement satisfies the equation.

Other 4 statement didn't satisfy the equation.

So, first statement is correct.

Learn more about rate of reading here:

brainly.com/question/4459849

#SPJ1

7 0

1 year ago

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Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

Which expression can be used to find the surface area of the following rectangular prism?

PolarNik [594]

Answer:

C.

Step-by-step explanation:

3 times 2 is 6, 2 times 5 is 10, 5 times 3 is 15. However you need 2 for each since there are 3 sets of two equal faces. So it will be 6+6+10+10+15+15

4 0

3 years ago

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