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shepuryov [24]
3 years ago
8

Pls help i really need help asap

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Answer to 8:

February may April march

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Triangle MRN is created when an equilateral triangle is folded in half.
Rus_ich [418]

The value of y based on the values given ib the equilateral triangle will be 4.

<h3>How to illustrate the triangle?</h3>

From the information given, MN is one of the sides of the equilateral triangle. Therefore, side MR will be:

= 1/2 × 8 = 4

In the above, it should be noted that MR was calculated since it's half of the value of MN which is 8.

Here, value of y based on the values given ib the equilateral triangle will be 4.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ1

6 0
2 years ago
I need help with easy math please
Ivahew [28]

Answer:

1. 16

2. 12

3. 0

4. 17

5. 16

6. 4

7. 32

8. 36

9. 1/18

Step-by-step explanation:

7 0
4 years ago
Can someone please explain how to solve such a mean and sneaky problem? Please?
Lelu [443]

Answer:

all real numbers

Step-by-step explanation:

simplify each side of the inequality

26 + 6b -- already fully simplified

2(3b + 4) → 6b + 8

26 + 6b ≥ 6b + 8

subtract 6b from both sides

26 ≥ 8

since this expression is true (26 is greater than 8), then the solution is all real numbers. any value could take the place of b because in the end, it will be canceled out by itself, resulting in 26 ≥ 8

4 0
3 years ago
I need help fast!!!
topjm [15]
Where’s the question?
8 0
3 years ago
Helpppppppppppppppppppp
Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
3 years ago
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