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lina2011 [118]
3 years ago
7

I don’t understand number 1 and I need help solving it?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

  1/4 cup more

Step-by-step explanation:

1/2 + x = 3/4       ===>       0.5 + x = 0.75

                                        -0.5        -0.5

                                                   x = 0.25

         0.25 = 25/100 = 1/4 cup

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Simplify: 22 + 6(3) – 7<br><br> Simplify: 5x − 2y + 3z − 2x − y + 4z
guapka [62]

Answer:

1. 33

2. 3x - 3y + 7z

Step-by-step explanation:

combine like terms on the second one.

3x - 3y + 7z

solve for the first one 22 + 18 - 7

18 - 7 = 11

11 + 22 = 33

3 0
3 years ago
Please help as soon as possible will mark as brainliest
scZoUnD [109]

i think its c.

hope this helpped

7 0
3 years ago
The diagonals of a rhombus intersect at the point (0,4). If one endpoint of the longer diagonal is located at point (4,10), wher
Wewaii [24]

Answer:

The other endpoint is located at (-4,-2)

Step-by-step explanation:

we know that

The diagonals of a rhombus bisect each other

That means-----> The diagonals of a rhombus intersect at the midpoint of each diagonal

so

The point (0,4) is the midpoint of the two diagonals

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

we have

M=(0,4)

(x_1,y_1)=(4,10)

substitute

(0,4)=(\frac{4+x_2}{2},\frac{10+y_2}{2})

<em>Find the x-coordinate x_2 of the other endpoint</em>

0=\frac{4+x_2}{2}

x_2=-4

<em>Find the y-coordinate y_2 of the other endpoint</em>

4=\frac{10+y_2}{2}

8=10+y_2

y_2=-2

therefore

The other endpoint is located at (-4,-2)

4 0
4 years ago
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter
Goshia [24]

Answer:

The question is incomplete, this is the complete question.;

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.

The answer to the question is;

the probability of this occurring is 1/27

Step-by-step explanation:

Let n(N) =5 ( the number of nickels)

n(D) =5 ( the number of dimes) and

n(Q) = 5 ( the number of quarters)

P(N)= 5/15=1/3 (prob of picking a nickel)

P(D) =5/15=1/3 (prob of picking a dime)

P(Q) = 5/15= 1/3 (prob of picking a quatre)

The probability of picking the three= P(N)×P(D)×P(Q)

= 1/3×1/3×1/3

= 1/27

7 0
4 years ago
Help easy math question
tangare [24]

i believe the answer is the third option              

8 0
3 years ago
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