25% of the circles are shaded. You would find this by dividing 3/12! Have a good day!
Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.
Step-by-step explanation:
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Answer: 18%</h3>
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Explanation:
Convert each percentage to decimal form
- 30% converts to 0.30
- 60% converts to 0.60
Then multiply the decimal values
0.30*0.60 = 0.18
That converts to 18%
So there's an 18% chance that both events happen at the same time. In other words, there's an 18% chance of the temperature falling below zero and the bus being late.
Answer: 28
Step-by-step explanation:
Simplifying
2x + 16 = 3x + -12
Reorder the terms:
16 + 2x = 3x + -12
Reorder the terms:
16 + 2x = -12 + 3x
Solving
16 + 2x = -12 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
16 + 2x + -3x = -12 + 3x + -3x
Combine like terms: 2x + -3x = -1x
16 + -1x = -12 + 3x + -3x
Combine like terms: 3x + -3x = 0
16 + -1x = -12 + 0
16 + -1x = -12
Add '-16' to each side of the equation.
16 + -16 + -1x = -12 + -16
Combine like terms: 16 + -16 = 0
0 + -1x = -12 + -16
-1x = -12 + -16
Combine like terms: -12 + -16 = -28
-1x = -28
Divide each side by '-1'.
x = 28
Simplifying
x = 28
Complete question :
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an
hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.
Let H represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1 answer:
A. 28 + 65H < 250
B. 28 + 65H > 250
C. 65 + 28H < 250
D. 65 +28H > 250
2) What is the largest whole number of hours that Anand can afford?
Answer:
65 + 28H < 250
Number of hours Anand can afford = 6 hours
Step-by-step explanation:
Given the following information :
Initial hourly rate = $65
Hourly rate = $28
Number of hours worked (whole number) = H
Maximum budgeted amount to spend = $250
Therefore ;
(Initial charge + total charge in hours) should not be more than $250
$65 + ($28*H) < $250
65 + 28H < 250
Number of hours Anand can afford :
65 + 28H < 250
28H < 250 - 65
28H < 185
H < (185 / 28)
H < 6.61
Sinve H is a whole number, the number of hours he can afford is 6 hours