Answer:
Total number of milkshakes sold on Monday = 300
Number of milkshakes without whipped cream = 90
Step-by-step explanation:
Given:
Adrienne adds whipped cream to 210 milk shakes which is 70% of the total milk shakes sold.
To find the total milkshakes sold.
Solution:
Let the total number of milkshakes sold on Monday be =
Percentage of milkshakes with whipped cream added to them = 70%
Number of milk shakes with added whipped cream can be given as:
⇒
⇒
⇒ [Representing percent in fraction form]
⇒ [evaluating in decimals]
We know that the number of milkshakes with whipped cream added to them = 210.
So, we have:
Solving for
Dividing both sides by 0.7
∴
Thus, total number of milkshakes sold on Monday = 300
Number of milkshakes without whipped cream = = 90
Explanation:
Since we have given that
Speed at which Eugene walked all the way to school = 3 mph
After realizing that she forgot her math book, she ran back
Speed at which Eugene walked back to her house = 7 mph
Let the distance between her house and her school be x
According to question,
Hence,
9514 1404 393
Answer:
1. asymptotes: x=-6, x=6, y=0; zero: x=0
2. 20 blue fish
Step-by-step explanation:
1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.
The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.
The zero is where the numerator is zero, at x=0.
In summary:
__
2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.
blue fish = 2×10 = 20 fish
<em><u>Check</u></em>
There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.
<u><em>Additional comment</em></u>
I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...
r = 60%(r + b) . . . . reds are 60% of the total
r - b = 10 . . . . . . . . 10 more reds than blues
We want the value of b, so we can eliminate r by substituting for it:
r = 10 + b . . . . from the second equation above
(10 +b) = 0.60((10 +b) + b) . . . . substitute for r
10 +b = 6 + 1.2b . . . simplify
4 = 0.2b . . . . subtract b+6
20 = b . . . . . . multiply by 5 (there are 20 blue fish)
