Given XYZ, if XY ≈ YZ, and m

Mathematics

1 answer:

levacccp [35]3 years ago

6 0

Answer: m<Z = 79

Step-by-step explanation:

180 - 22 = 158

158/2 = 79

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P1= (5,-4); p2=(8,-3);p3=(7,-10) find the length of each side of the triangle determined by three points

Dima020 [189]

so the points are, from P1 to P2, namely P1P2, and from P2 to P3, namely P2P3, and from P3 back to P1, namely P3P1.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P1(\stackrel{x_1}{5}~,~\stackrel{y_1}{-4})\qquad P2(\stackrel{x_2}{8}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ P1P2=\sqrt{[8-5]^2+[-3-(-4)]^2}\implies P1P2=\sqrt{(8-5)^2+(-3+4)^2} \\\\\\ P1P2=\sqrt{3^2+1^2}\implies \boxed{P1P2=\sqrt{10}}\\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P2(\stackrel{x_2}{8}~,~\stackrel{y_2}{-3})\qquad P3(\stackrel{x_2}{7}~,~\stackrel{y_2}{-10}) \\\\\\ P2P3=\sqrt{[7-8]^2+[-10-(-3)]^2}\implies P2P3=\sqrt{(7-8)^2+(-10+3)^2} \\\\\\ P2P3=\sqrt{(-1)^2+(-7)^2}\implies P2P3=\sqrt{50}\implies \boxed{P2P3=5\sqrt{2}}\\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P3(\stackrel{x_2}{7}~,~\stackrel{y_2}{-10})\qquad P1(\stackrel{x_1}{5}~,~\stackrel{y_1}{-4}) \\\\\\ P3P1=\sqrt{[5-7]^2+[-4-(-10)]^2}\implies P3P1=\sqrt{(5-7)^2+(-4+10)^2} \\\\\\ P3P1=\sqrt{(-2)^2+6^2}\implies P3P1=\sqrt{40}\implies \boxed{P3P1=2\sqrt{10}}$

5 0

3 years ago

Which shows a way to take apart 8 .ans are. 9-9=0. 8-7=1. 9-8=1. 8+8=16.

Sergio039 [100]

<span>To take appart 8 means to subtract 8 from a number and then you will have two parts one with the number 8 and the other with the difference. So, if you want to take appart 8 from 9, you make 9 - 8 = 1. Which means that you can have 8 and 1 sperated from 9. So the answer is the third option 9 - 8 = 1.</span>

3 0

3 years ago

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Karolina [17]

Answer:

The new balance will be $385.04.

Step-by-step explanation:

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