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melamori03 [73]
3 years ago
8

Find the sequence of -1, 1, __, 5, __

Mathematics
1 answer:
marin [14]3 years ago
7 0
The missing numbers are 3, and 7
the pattern is +2 to each number
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Algebraic expression for 6 notebooks at S dollars
swat32
6=S
therefore, to find one you must divide both sides by 6
the answer should be = 1=S/6
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4 years ago
Please help me :((((
Mila [183]
1. x + 49 = -3x + 1
4x = -48
x = -12

2. 7x + 23 + 4x + 25 = 180
11x + 48 = 180
11x = 132
x = 12
5 0
3 years ago
Find 1112+(−712)1112+(−712). Write your answer as a fraction in simplest form.
Julli [10]
I got -791344 or -791344/1
6 0
4 years ago
Read 2 more answers
First to answer gets brainliest
olganol [36]

Answer:

y = 4x - 9

Step-by-step explanation:

Take 2 points:

(0,-9) and (4,7)

Find the slope:

(7 - (-9))/(4 - 0)

16/4 = 4

so we have y = 4x + b

Now find b:

Insert a point for y and x:

7 = 4(4) + b

7 = 16 + b

b = -9

y = 4x - 9

8 0
3 years ago
A business school professor uses multiple choice tests. Each question on his exams has five possible answers which are assumed t
avanturin [10]

Answer:

a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution

b. The degrees of freedom do you have for this test is 4

c.  The calculated value of the test statistic is 9.250

Step-by-step explanation:

a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.

b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:

degrees of freedom=k-1

degrees of freedom=5-1

degrees of freedom=4

c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:

expected frecuency=total observed frecuency/total number of category

expected frecuency=1,000/5

expected frecuency=200

Hence, to calculate the value of the test statistic we have to calculate the following formula:

x∧2=∑(fo-fe)∧2/fe

=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2

=9.250

The calculated value of the test statistic is 9.250

7 0
3 years ago
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