see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10
10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7
Answer:
Step-by-step explanation:
To find the distance between two points, use the distance formula.
The distance formula is:
Let (3,-4) be x₁ and y₁ and let (5,4) be x₂ and y₂. Therefore:
Simplify:
Square:
Add:
Simplify:
Simplify:
C.) -1.
Explanation: 4 + -5 = -1. When you have a negative number plus a positive you subtract. Then take the highest numbers positive or negative symbol. Hope that helps.
