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Natasha_Volkova [10]
2 years ago
5

Find the sum: 35,076 + 6,825 = ______.

Mathematics
2 answers:
Tcecarenko [31]2 years ago
5 0
41,901




that’s the answer
Basile [38]2 years ago
3 0

Answer:

41,901

Step-by-step explanation:

Hi! Okay, let's get started

  35,076

+

  06, 825

------------------

    41, 901

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

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ASAP 30 + Brainliest <br><br> Please only solve 2 - 5
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<u>QUESTION 2a</u>


We want to find the area of the given right angle triangle.


We use the formula

Area=\frac{1}{2}\times base\times height

The height of the triangle is =a cm.

The base is 12cm.


We substitute the given values to obtain,


Area=\frac{1}{2}\times 12\times a cm^2.

This simplifies to get an expression for the area to be

Area=6a cm^2.





<u>QUESTION 2b</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


The length of the rectangle is l=7cm and the width of the rectangle is w=ycm.


We substitute the values to obtain the area to be


Area=7 \times y


The expression for the area is

Area=7y


<u>QUESTION 2c.</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


The length of the rectangle is l=2x cm and the width of the rectangle is w=4 cm.


We substitute the values to obtain the area to be


Area=2x \times 4


The expression for the area is

Area=8x


<u>QUESTION 2d</u>


The given diagram is a square.

The area of a square is given by,

Area=l^2.


where l=b m is the length of one side.


The expression for the area is

Area=b^2 m^2


<u>QUESTION 2e</u>

The given diagram is an isosceles triangle.


The area of this triangle can be found using the formula,

Area=\frac{1}{2}\times base\times height.

The height of the triangle is 4cm.


The base of the triangle is 6a cm.


The expression for the area is

Area=\frac{1}{2}\times 6a \times 4cm^2


Area=12a cm^2


<u>QUESTION 3a</u>

Perimeter is the distance around the figure.

Let P be the perimeter, then

P=x+x+x+x

The expression for the perimeter is

P=4x mm


<u>QUESTION 3b</u>

The given figure is a rectangle.


Let P, be the perimeter of the given figure.

P=L+B+L+B


This simplifies to

P=2L+2B

Or

P=2(L+B)


<u>QUESTION 3c</u>

The given figure is a parallelogram.

Perimeter is the distance around the parallelogram

Perimeter=3q+P+3q+P

This simplifies to,


Perimeter=6q+2P

Or

Perimeter=2(3q+P)



<u>QUESTION 3d</u>

The given figure is a rhombus.

The perimeter is the distance around the whole figure.


Let P be the perimeter. Then

P=5b+5b+5b+5b


This simplifies to,

P=20b mm


<u>QUESTION 3e</u>

The given figure is an equilateral triangle.

The perimeter is the distance around this triangle.

Let P be the perimeter, then,

P=2x+2x+2x


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P=6x mm


QUESTION 3f

The figure is an isosceles triangle so two sides are equal.


We add all the distance around the triangle to find the perimeter.


This implies that,


Perimeter=3m+5m+5m


Perimeter=13m mm



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The given figure is a scalene triangle.

The  perimeter is the distance around the given triangle.

Let P be the perimeter. Then

P=(3x+1)+(2x-1)+(4x+5)


This simplifies to give us,


P=3x+2x+4x+5-1+1


P=9x+5


<u>QUESTION 3h</u>

The given figure is a trapezium.

The perimeter is the distance around the whole trapezium.

Let P be the perimeter.

Then,

P=m+(n-1)+(2m-3)+(n+3)


We group like terms to get,

P=m+2m+n+n-3+3-1

We simplify to get,

P=3m+2n-1mm


QUESTION 3i

The figure is an isosceles triangle.

We add all the distance around the figure to obtain the perimeter.

Let P be the perimeter.


Then P=(2a-b)+(a+2b)+(a+2b)


We regroup the terms to get,

P=2a+a+a-b+2b+2b

This will simplify to give us the expression for the perimeter to be

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The given figure is a square.


The area of a square is given by the formula;

Area=l^2

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We substitute this value to obtain;

Area=(2m)^2


This simplifies to give the expression of the area to be,

Area=4m^2


QUESTION 4b

The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=5a cm is the length of the rectangle and w=6cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =5a \times 6


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QUESTION 4c


The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=7y cm is the length of the rectangle and w=2x cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =7y \times 2x

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The given figure is a rectangle.


The formula for finding the area of a rectangle is

Area=l\times w.

where l=3p cm is the length of the rectangle and w=p cm is the width of the rectangle.

We substitute the values into the formula to get,

Area =3p \times p

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See attachment for the continuation


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