Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
A. they both have 4 right angles
B. a sqaure has 4 even sides, a rectangle doesnt
c. they both have 4 even sides
d. rhombi has 2 acute and 2 obtuse angles
e. Parallelograms are a quadrilateral where diagonals bisect each other, opposite sides are parallel by definition, opposite sides are congruent and consecutive angles are supplementary.
Blue: = because the equal sign is stating that it’s the same.
Answer:
5
Step-by-step explanation:
15-7 is 8 and then 8 - 3= 5
