Question

A 60 W light bulb has a resistance of 880 Ω

Answer 1

$\bf{ \underline{Given:- }}$

$\sf{• \: Power \: (P) = 60 \: w}$

$\sf{• \: Resistance \: (R) = 880 \: Ω}$

$\bf{ \underline{To \: Find :- }}$

$\sf• \: The \: Current \: (I).$

$\huge\bf{ \underline{ Solution :- }}$

$\sf We \: know \: that,$

$\bf \red {\bigstar{ \: P = I^{2} R}}$

$\rightarrow \sf 60 = I^{2} \times 880$

$\rightarrow \sf \frac{60}{880} = I^{2}$

$\rightarrow \sf I^{2} = 0.0681$

$\rightarrow \sf I = \sqrt{0.0681}$

$\rightarrow \sf I = 0.261 \: \: (approx.)$

$\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)$