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GuDViN [60]
3 years ago
7

A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly

at a rate of 1 m/s2 for 4 seconds. It then continues at a constant speed for 12.9 seconds, before getting tired and slowing down with constant acceleration coming to rest 66 meters from where it started. The tortoise accelerates uniformly for the entire distance, finally catching the hare just as the hare comes to a stop. 1)How fast is the hare going 1.6 seconds after it starts
Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

v = 4 m/s

Explanation:

Given that,

Initial speed of hare, u = 0

The hare accelerates uniformly at a rate of 1 m/s² for 4 seconds.

We need to find how fast is the hare going 1.6 seconds after it starts. Let the speed be v. So,

v = u+at

Substitute all the values,

v = 0+1×4

v = 4 m/s

So, the required speed of the hare is 4 m/s after it starts.

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6 0
3 years ago
It is dangerous to stand near the railway leak when train passing by,why?​
4vir4ik [10]

Answer:

Because a person may be pulled in the direction of the moving train. Thereby causing accident

Explanation:

According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.

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3 years ago
Why do atoms form bonds by donating, accepting or sharing electrons with other atoms?
sineoko [7]

Answer:

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Explanation:

i hope it helped

7 0
3 years ago
Why did Isaac Newton come up with the three laws of motion
son4ous [18]
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3 0
4 years ago
The football players collide head-on in midair while trying to catch a thrown football. The first player is 95.0 kg and has an i
sukhopar [10]

Answer:

v=0.8m/s

Explanation:

To solve the problem, we can use collisions theory from classical physics

If we analyze the players before and after the collision we got:

p_{1}=p_{2}

Since the cling together

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v

From the exercise we know that the first player is 95.0 kg and has an initial velocity of 6.00 m/s, while the second player is 115 kg and has an initial velocity of –3.50 m/s.

v=\frac{m_{1}v_{1}+m_{2}v_{2}}{(m_{1}+m_{2})}=\frac{(95kg)(6m/s)+(115kg)(-3.5m/s)}{(95+115)kg}

v=0.797m/s=0.8m/s

3 0
3 years ago
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