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4 years ago

Lenny loves physics and math. In which Energy career pathway would these interests be the most helpful?

Physics

2 answers:

vazorg [7]4 years ago

3 0

Answer:

it is D

Explanation:

cause i took the test

worty [1.4K]4 years ago

3 0

Answer:

The correct answer is d = transmission

Explanation:

Hello! Let's solve this!

The transmission of energy occurs when two particles collide and the energy of one is transmitted and accumulates with the energy that the other particle has. In order to study this subject, knowledge of physics and mathematics is very important.

The correct answer is d = transmission

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What are the function of mercury barometer

Orlov [11]

Answer:

A mercury barometer is an instrument used to measure atmospheric pressure in a certain location and has a vertical glass tube closed at the top sitting in an open mercury-filled basin at the bottom. Mercury in the tube adjusts until the weight of it balances the atmospheric force exerted on the reservoir.

Explanation:

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3 years ago

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How many mL of water would be displaced by 408 g of lead

Natasha2012 [34]

For this, we must know the density of lead. This is 11.36 grams per cubic centimeter. The mass present is 408 grams. Therefore, the volume occupied will be:
408 / 11.36 = 35.9 cubic centimeters. This is the volume of water that will be displaced.
Now, we know that one cubic centimeter is equivalent to one mL. Therefore,
35.9 ml of water will be displaced.

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3 years ago

A dog sits 2.6 m from the center of a merry- go-round. a) If the dog undergoes a 1.7 m/s^2 centripetal acceleration, what is the

alexgriva [62]

Answer:

a) v= 2.1 m/s

b) ω = 0.807 rad/s

Explanation

Conceptual analysis :

The dog and the merry-go- round describes a circular motion, then, the following formulas apply :

$a_{c} =\frac{v^{2} }{r}$ Formula (1)

v = ω *r Formula (2)

Where:

$a_{c}$ : Centripetal acceleration(m/s²)

v: linear speed or tangential (m/s)

r : radius of the circle (m)

ω : angular speed ( rad/s)

Data

r= 2.6 m

$a_{c}$ = 1.7 m/s²

Problem develpment

a) We replace data in the formula 1 to calculate the dog's linear speed(v):

$a_{c} =\frac{v^{2} }{r}$

$1.7 =\frac{v^{2} }{2.6}$

$v^{2} =1.7*2.6 = 4.42$

$v=(\sqrt{4.42})\frac{m}{s}$

v= 2.1 m/s

b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).

v = ω *r

2.1 = ω *2.6

ω = 2.1/2.6

ω = 0.807 rad/s

6 0

3 years ago

How do i make someone like me before they talk to me

pogonyaev

Be easy-going and be yourself.

8 0

3 years ago

Tres litros de oxigeno gaseoso a 15 grados centígrados y a presión atmosférica (1atm), se lleva a una presión de 10mm de Hg. ¿ c

lana [24]

Answer:

Three liters of gaseous oxygen at 15 degrees Celsius and at atmospheric pressure (1atm), is brought to a pressure of 10mm Hg. What will be the volume of the gas now if the temperature has not changed?

Explanation:

Given that, the temperature is constant

Then, using gay Lussac law

P1•V1 / T1 = P2•V2 / T2

Since temperature is constant

Then, T1 = T2 = T and they cancels out

So, we are left with

P1•V1 = P2•V2

Given that, .

Initial volume

V1 = 3 litres.

Initial pressure

P1 = 1atm = 101325 Pa

Final pressure

P2 = 10mmHg = 1333.22 Pa

Then, we want to find the final volume V2

Make V2 subject of formula.

V2 = V1•P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litres

So, the final volume is 288 litres.

In Spanish

Dado que la temperatura es constante

Luego, usando la ley gay de Lussac

P1 • V1 / T1 = P2 • V2 / T2

Como la temperatura es constante

Entonces, T1 = T2 = T y se cancelan

Entonces, nos quedamos con

P1 • V1 = P2 • V2

Dado que, .

Volumen inicial

V1 = 3 litros.

Presión inicial

P1 = 1atm = 101325 Pa

Presión final

P2 = 10 mmHg = 1333.22 Pa

Entonces, queremos encontrar el volumen final V2

Hacer V2 sujeto de fórmula.

V2 = V1 • P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litros

Entonces, el volumen final es de 288 litros

8 0

4 years ago