Answer:
A possible solution is that radius of cone B is 2 units and height is 36 units
Step-by-step explanation:
The volume of a cone is given by
![V=\frac{1}{3}\pi r^2 h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%20h)
where
r is the radius
h is the height
Here we are told that both cones A and B have the same volume, which is:
![V_A=\frac{1}{3}\pi r_A^2 h_A = 48 \pi](https://tex.z-dn.net/?f=V_A%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r_A%5E2%20h_A%20%3D%2048%20%5Cpi)
And
(2)
We also know that cone A has radius 6 units:
![r_A=6](https://tex.z-dn.net/?f=r_A%3D6)
and height 4 units:
![h_A=4](https://tex.z-dn.net/?f=h_A%3D4)
For cone B, from eq.(2), we get
![\frac{1}{3}r_B^2 h_B = 48\\r_B^2 h_B = 48\cdot 3 =144](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dr_B%5E2%20h_B%20%3D%2048%5C%5Cr_B%5E2%20h_B%20%3D%2048%5Ccdot%203%20%3D144)
One possible solution for this equation is
![r_B = 2\\h_B = 36](https://tex.z-dn.net/?f=r_B%20%3D%202%5C%5Ch_B%20%3D%2036)
In fact in this case, we get:
![r_B^2 h_B = (2)^2\cdot 36 = 4\cdot 36 = 144](https://tex.z-dn.net/?f=r_B%5E2%20h_B%20%3D%20%282%29%5E2%5Ccdot%2036%20%3D%204%5Ccdot%2036%20%3D%20144)
Therefore a possible solution is that radius of cone B is 2 units and height is 36 units, and we know that in this case Cone B has the same volume as cone A because it is told by the problem.
Answer:
For college degree the first box is 5
Step-by-step explanation:
Answer:
a) (2,2)
Step-by-step explanation:
as X=2 and y=2
y=x
E(n)=2n
E(21)=2(21)
E(21)=42
B works
see others
A. E(15)+E(6)=30+12=42, yep
B. 42 is confirmed
C is wrong
D. E(11)+10=22+10=32, nope
answer is A and B
Answer: B. Unit
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Hope this helps :p