Answer: No, we don't have a right triangle
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Explanation:
If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.
Here we have a = 2, b = 5 and c = 7.
So...
a^2+b^2 = c^2
2^2+5^2 = 7^2
4+25 = 49
29 = 49
The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do <u>not</u> have a right triangle.
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In contrast, consider the classic 3-4-5 right triangle
a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).
Answer:
The factored form of this would be 16(4b - c)
Step-by-step explanation:
In order to find this, look for the greatest common factor of 16 and 64. You can do this by listing out their factors. Once this is done and we identify 16 as the GCF, we can then put that on the outside of the parenthesis and divide all the terms inside by that number.
you cant really show that on this thing so.... and im not getting enough points for that so ..........
The y intercept is 2.25 and x intercept is -3
Answer:6
Step-by-step explanation:Which sequence is modeled by the graph below?
10
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8
• (5,8)
7 7.
8
5
4 +
. (4,4)
3
2
• (3, 2)
1
.
(2, 1)
1 2 3
empl
4
5
6 7
8 9 10
