Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
Answer:
Volume of the bar=10 X 4 X 5=200 cm^3
Mass=200 X 19.3=3,860 grams
Mass=3.86 Kilograms
Explanation:
Answer:
a) [ Ca2+ ] = 3.347 E-4 mol/L
b) [ Ca2+ ] = 1.5 E-8 mol/L
Explanation:
S S 2S......in the equilibrium
⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S )² = 4S³
⇒ S = ∛ ( 1.5 E-10 / 4 )
⇒ S = ∛ 3.75 E-11
⇒ S = 3.347 E-4 mol/L
⇒ [ Ca2+ ] = S = 3.347 E-4 mol/L
b) NaF ↔ Na+ + F-
0.10 M 0.10 0.10
S S 2S + 0.10
⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S + 0.10 )²
∴∴ the Concentration: 0.10 M >>>> Ksp ( 1.5 E-10 ), son we can despise S as adding.
⇒ 1.5 E-10 = S * ( 0.10 )² = 0.01 S
⇒ S = 1.5 E-10 / 0-01
⇒ S = 1.5 E-8 mol/L
⇒ [ Ca2+ ] = S = 1.5 E-8 mol/L
Answer. Answer: Scientists study how things work, while engineers create new things
Explanation:
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