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marin [14]
3 years ago
8

What is the lowest possible number of moves in solitaire?

Chemistry
1 answer:
jek_recluse [69]3 years ago
7 0
<span>Theoretically, for a very optimal deal of Solitaire it would only take 76 moves for 1-deal, or 60 for 3-deal (one for each card to move into the Foundations and some overflow for dealing from the deck).

source: </span>https://www.quora.com/What-is-the-minimum-number-of-moves-required-to-win-in-Solitaire
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Which missing item would complete this beta decay reaction?
Karo-lina-s [1.5K]
The question is incomplete. Complete question is attached below:
.................................................................................................................

Correct Answer is : 54 131Xe

Reason: 
Emission of beta particle from radioactive material increases atomic number by one, but atomic mass number donot change.

In present case, the reactant is 53 131 I. When, iodine emits beta particle i.e. electron, it atomic number increases by one. Hence, it gets converted into Xe. Atomic number of Xenon is 54. 

7 0
3 years ago
Read 2 more answers
g Ethanol boils at 78.4 °C with \DeltaΔHvap = 38.6 kJ/mol. A 0.200-mol sample of ethanol is heated from some colder temperature
andrezito [222]

Answer:

8.77 kilo Joules  will be the total amount of heat required for both the heating and the vaporizing.

Explanation:

Moles of ethanol of ethanol = 0.200 mol

Heat required to heat 0.200 moles of ethanol = Q = 1.05 kJ

Enthalpy of vaporization of ethanol = \Delta H_{vap}=38.6 kJ/mol

Heat required to vaporize 0.200 moles of ethanol = Q'

Q'=\Delta H_{vap}\times 0.200 mol=38.6 kJ/mol\times 0.200 mol=7.72 kJ

Total heat required to fore heating and the vaporizing :

= Q + Q' = 1.05 kJ + 7.72 kJ = 8.77 kJ

8.77 kilo Joules  will be the total amount of heat required for both the heating and the vaporizing.

7 0
4 years ago
Nitric oxide reacts with chlorine gas according to the reaction: 2 NO( g) + Cl2( g) ∆ 2 NOCl( g) Kp = 0.27 at 700 K A reaction m
11Alexandr11 [23.1K]

Answer:  The initial partial pressures of NO and Cl_2 is 139.4 torr.

Explanation:

The equilibrium reaction is

                           2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

initially conc.         p            p                  0

At eqm.                p-2x        p-x               2x

Given: p_{NOCl}= 2x= 115torr

x=57.5 torr

The expression for equilibrium constant is :

K_p=\frac{p_{NOCl}^2}{p_{NO}^2\times p_{Cl_2}}

p_{NOCl} = 2x =115 torr

p_{NO} = (p-2x) = p-115 torr

p_{Cl_2} = (p-x)= p-57.5 torr

Now put all the given values in this expression, we get

0.27=\frac{(115)^2}{(p-115)^2\times (p-57.5)}

p=139.4torr

Therefore, the initial partial pressures of NO and Cl_2 is 139.4 torr.

8 0
4 years ago
How many moles of CaCI are present in 60.0mL of a 0.10 M CaCI2 solution?
balandron [24]

Answer:

0.006 mol of CaCl2 are present

Explanation:

Use dimensional analysis for this:

60.0 mL CaCl2/1  * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol

If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.

**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.

Hope this helps :)

4 0
3 years ago
Anyone knows how to do this-
adelina 88 [10]

Explanation:

The number of protons in the element C^12 (Carbon) is 6, number of electrons 12 and number of Neutrons is 6, same as the number of protons it contains

C^13 has 13 electrons, 6 protons and 7 Neutrons this one's neutron number is different from proton number because it's an isotope

Na^-1 has gained an electron so the number of electrons it has = 24 and the number of protons shown as 11 which means there are 23 - 11 = 12 Neutrons

O^-2 has gained two electrons and got 18 electrons in total, 8 protons and 8 neutrons

6 0
3 years ago
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