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natulia [17]
3 years ago
11

Snow is approximately 1/8 as heavy as water how many inches of snow would it take to weigh as much as 3 1/2inches of rain fall

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0
Snow is 1/8 as heavy as water.
That means 1 cu. Inch of rainfall results in 1/8 cu. Inch of snow
So, 3.5 cu. Inch of rainfall results in [ 1/8* 3.5] cu. Inch of snow
0.4375 cu. Inch of snow
Therefore 0.4375 cu. Inches of snow would weigh as much as 3.5 cu. inches of rainfall.
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Steve travelled from Ashton to Barnfield.
USPshnik [31]

Answer:

67.1

Step-by-step explanation:

Given That:

Time = 200 minutes = 3.5 hours

Distance = 235 miles

We Know That:

Speed = Distance / Time

SO, Speed = 235 divided by 3.5 = 67.1428571

Round this 3sf = 67.1

Hope this helps.

5 0
3 years ago
What does pi mean? I foro=got..
Furkat [3]

Answer:

3.14159265359

Step-by-step explanation:

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5 0
3 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
3 years ago
Have a free brainliesttttttttttttttttttt
lilavasa [31]
Ok me pls thank you so much you are a heavenly angel
7 0
3 years ago
Y varies directly with X if y equals 39 when x equals 3 What is the value of y when x equals 2
igomit [66]

Answer:

y = 26 when x = 2

Step-by-step explanation:

Y varies directly with X

y= kx

39 = 3k

k = 13

y = 13x

y(2)= 13(2) = 26

4 0
3 years ago
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