3 years ago

Find the slope of the line that passes through these points. (2, 2) and (4, 4)

Mathematics

1 answer:

malfutka [58]3 years ago

5 0

Answer:

Step-by-step explanation:

We can find the slope using the slope formula

m = ( y2-y1)/(x2-x1)

= ( 4-2)/(4-2)

= 2/2

= 1

You might be interested in

Yusef typed a 36 word paragraph in 2/3 minute.what is his typing speed in words per minute

lilavasa [31]

Words over minutes.
So 36/(2/3)
Basically saying
36 * (3/2) = 54

5 0

2 years ago

What is the GCF of 42 and 91?

Neko [114]

Answer:

Step-by-step explanation:

7 0

3 years ago

Expression for all solutions to the equation cos(theta) = 1 + 3cos(theta)

OleMash [197]

$\cos\theta=1+3\cos\theta\implies 0=1+2\cos\theta\implies \cos\theta=-\dfrac12$

On the unit cirlce, the cosine of an angle is negative whenever the angle falls in the interval $\dfrac\pi2$ .

If you recall your special triangles, this cosine occurs for angles of $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ .

More generally, this occurs for $x=\dfrac{2\pi}3+2n\pi$ and $x=\dfrac{4\pi}3+2n\pi$ , where $n$ is an integer.