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3 years ago

Fill in the missing number to name a fraction equivalent to 6/8

Mathematics

2 answers:

mariarad [96]3 years ago

5 0

Answer:

3/4

Step-by-step explanation:

6 and 8 are both divisible by 2.

6/2 = 3

8/2 = 4

3/4 (.75)

Nataly [62]3 years ago

4 0

3/4 would be a fraction, equivalent to 6/8.

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Hi please help me no links thank you

olya-2409 [2.1K]

Step-by-step explanation: (I'm not gonna' do it all for you tho)

to convert from percent to fraction:

70% = $\frac{70}{100} =\frac{7}{10}$

to convert from fraction to percent:

$\frac{11}{20}=\frac{55}{100}$ = 55%

to convert from fraction to decimal:

$\frac{3}{25} =\frac{12}{100} =0.12$

to convert from decimal to fraction:

$1.25=\frac{125}{100} =1\frac{25}{100} =1\frac{1}{4}$

to convert from percent to decimal:

0.2% = $\frac{0.2}{100} =0.002$

to convert from decimal to percent:

$0.4= (0.4*100)$ % = 40%

With that, you can solve the rest on your own

4 0

3 years ago

Is a dilation an example of a rigid motion. Explain your response.

Likurg_2 [28]

Answer:

This differs from non-rigid motion, like a dilation, where the size of the object can increase or decrease. When working with rigid motion, you will typically see two objects that show the transformation.

Step-by-step explanation:

5 0

3 years ago

Sally has seventy dollars to spend on eight books. After buying them she had thirteen dollars. How much did each book cost?

Anit [1.1K]

Answer:

7.13 each

Step-by-step explanation:

70 - 13 = 57. Divide 57/8 and get your answer

(7.125 rounded is 7.13)

5 0

3 years ago

Read 2 more answers

What is the solution of this equqtion? 1w= -17

devlian [24]

Answer:

-17

Step-by-step explanation:

1w= -17

(1)(-17)=

-17

5 0

3 years ago

Read 2 more answers

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago