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Paraphin [41]
3 years ago
6

Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides.

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

- 34 < x < 10

Step-by-step explanation:

Inequalities of the type | x | < a, always have a solution of the form

- a < x < a

given | x + 12 | + 5 < 27 ( subtract  5 from both sides )

| x + 12 | < 22, then

- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )

- 34 < x < 10


SSSSS [86.1K]3 years ago
3 0

Answer:

-34 < x < 10

Step-by-step explanation:

We have to solve absolute value inequality which means that we have to find the value of x.

| x+12 | +5 < 27

Adding -5 to both sides of above inequality,we get

| x+12 | +5-5 < 27-5

| x+12 | +0 < 22

| x+12 |  < 22

Since, we know that

| x | < a  ⇔ -a< x< a where a is any constant.

hence,

-22 < x+12 < 22

Adding -12 to each side of above inequality,we get

-22-12 < x+12-12 < 22-12

-34 < x+0 < 10

-34 < x < 10 which is solution of given inequality.

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maxonik [38]

Answer:

Las dimensiones del rectángulo son:

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largo = 20 cm

Step-by-step explanation:

Consideración:

La formula del perímetro de un rectángulo es:

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25% más grande = 125% = 125/100 = 1.25

Planteamiento:

2(a+b) = 72

b = 1.25a

a = longitud del ancho

b = longitud del largo

Desarrollo:

de la primer ecuación del planteamiento:

a+b = 72/2

a+b = 36

b = 36 - a        Ec. 3

Igualando la segunda ecuación del planteamiento con la Ec. 3:

1.25a = 36 - a

1.25a + a = 36

2.25 a = 36

a = 36/2.25

a = 16

de la Ec. 3:

b = 36 - a

b = 36 - 16

b = 20

Comprobación:

de la primera ecuación del planteamiento:

2(a+b) = 72

2(16+20) = 72

2*36 = 72

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2 years ago
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3 years ago
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8 0
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Effectus [21]

Answer:

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Step-by-step explanation:

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