Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides.
2 answers:
Answer:
- 34 < x < 10
Step-by-step explanation:
Inequalities of the type | x | < a, always have a solution of the form
- a < x < a
given | x + 12 | + 5 < 27 ( subtract 5 from both sides )
| x + 12 | < 22, then
- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )
- 34 < x < 10
Answer:
-34 < x < 10
Step-by-step explanation:
We have to solve absolute value inequality which means that we have to find the value of x.
| x+12 | +5 < 27
Adding -5 to both sides of above inequality,we get
| x+12 | +5-5 < 27-5
| x+12 | +0 < 22
| x+12 | < 22
Since, we know that
| x | < a ⇔ -a< x< a where a is any constant.
hence,
-22 < x+12 < 22
Adding -12 to each side of above inequality,we get
-22-12 < x+12-12 < 22-12
-34 < x+0 < 10
-34 < x < 10 which is solution of given inequality.
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