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3 years ago

Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides.

Mathematics

2 answers:

Feliz [49]3 years ago

8 0

Answer:

- 34 < x < 10

Step-by-step explanation:

Inequalities of the type | x | < a, always have a solution of the form

- a < x < a

given | x + 12 | + 5 < 27 ( subtract 5 from both sides )

| x + 12 | < 22, then

- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )

- 34 < x < 10

SSSSS [86.1K]3 years ago

3 0

Answer:

-34 < x < 10

Step-by-step explanation:

We have to solve absolute value inequality which means that we have to find the value of x.

| x+12 | +5 < 27

Adding -5 to both sides of above inequality,we get

| x+12 | +5-5 < 27-5

| x+12 | +0 < 22

| x+12 | < 22

Since, we know that

| x | < a ⇔ -a< x< a where a is any constant.

hence,

-22 < x+12 < 22

Adding -12 to each side of above inequality,we get

-22-12 < x+12-12 < 22-12

-34 < x+0 < 10

-34 < x < 10 which is solution of given inequality.

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3 years ago

In a political science class, test scores were determined to be 20 times the number of hours, h, the student studied plus 3.

V125BC [204]

Answer:

S = 20h + 3

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3 years ago

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Alexandra [31]

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3 years ago

(1/27)^x-6=27 Could I please have a step by step as well? Much appreciated!

Andrei [34K]

Answer:

$x = 7$

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

$\frac{1}{ {27}^{x - 8} } = 27$

2) Multiply both sides by 27^x - 8.

$1 = {27} \times 27^{1 + x - 8}$

3) Use the product rule: x^a x^b = x^a+b.

$1 = {27}^{1 + x - 8}$

4) Simplify 1 + x - 8 to x - 7.

$1 = {27}^{x - 7}$

5) Use Definition of Common Logarithm: b^a = x if and only if logb (x) = a.

$log_{27}1 = x - 7$

6) Use Change of Base Rule.

$\frac{ log_1 }{ log{27} } = x - 7$

7) Use rule of 1: log 1 = 0.

$\frac{0}{ log_{27}} = x - 7$

8) Simplify 0/log_27 to 0.

$0 = x - 7$

9) Add 7 to both sides.

$7 = x$

10) Switch sides.

$x = 7$

Therefor, the answer is x = 7.

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3 years ago

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