For the object described in question 2, what is the exact rate of change of s with respect to t when t = 1.5 seconds.
1 answer:
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Step-by-step explanation:
6 customers per hour (given mean)
Pdf is given by:
Pdf:
for
a)
&\text { c) }\\
&P(8<X<15)\\
&\begin{array}{l}
=P(X<15)-P(X<8) \\
=(1-\exp (-15 / \beta))-(1-\exp (-8 / \beta)) \\
=\exp (-8 / \beta)-\exp (-15 / \beta) \\
=e^{-0.8}-e^{-1.5} \\
=0.449329-0.22313 \approx 0.226199 \approx 0.2262 \\
\quad P(8<X<15)=0.2262
\end{array}
\end{aligned}
\begin{aligned}
&\text { d) }\\
&\begin{array}{l}
P(14<X<22) \\
=P(X<22)-P(X<14) \\
=(1-\exp (-22 / \beta))-(1-\exp (-14 / \beta)) \\
=\exp (-14 / \beta)-\exp (-22 / \beta) \\
=e^{-1.4}-e^{-2.2} \\
=0.246597-0.110803 \approx 0.135794 \approx 0.1358 \\
P(X<14 \cup X>22)=1-P(14<X<22)=1-0.1358=0.8642 \\
P(X<14 \cup X>22)=0.8642
\end{array}
\end{aligned}