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Helen [10]
3 years ago
11

Help this may be the last time

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0
I think the first is 107 and the second is 2. i’m not sure about the last two blanks but if they’re asking if it’s equivalent or not i think it is
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Anyone wanna help?please
timama [110]

\large\underline{\underline{\red{\rm\blue{\longmapsto} Step-by-step\: Explanation:-}}}

Given to points to us are :-

  • ( 3 , -6 )
  • ( -1 , -8 )

( As these are plotted on graph with yellow dots .)

Now , we can use Distance Formula , which is :-

\boxed{\pink{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}

Here ,

  • x1 = 3 .
  • x2 = -1.
  • y1 = (-6)
  • y2 = (-8).

<u>→ Substituting the respective values , </u>

⇒ Distance = √ [ { 3 - (-1)}² + { -6 -(-8)²} ] .

⇒ Distance = √ (3+1)² + (8-6)²

⇒ Distance = √ 4² + 2²

⇒ Distance = √ 16 + 4

⇒ Distance = √20 = √4 × √5

⇒ Distance = 4√5units .

<u>Hence the distance between two points is 4√5u.</u>

3 0
4 years ago
Write each number in SCENTIFic notation 64,000
adelina 88 [10]
Scientific notation means the numbers have to be between 1 and 10, so here is the answer as well as where to move the decimal

8 0
3 years ago
Multiplying a number by 4/5 then dividing by 2/5 is the same as multiplying what number?
prisoha [69]
Multiplying a number by 4/5 and then dividing by 2/5 is the same as multiplying by 2


5 0
3 years ago
Need asap will give brainliest
patriot [66]
Im not sure, but i think it should be
( -3, 1 )
( -3, -2 )
( -6, -3 )
7 0
3 years ago
Find the probability that a point is chosen randomly inside the rectangle is in each given shape...
BaLLatris [955]

Answer:

  1. <u>0.25</u>
  2. <u>0.85</u>

Step-by-step explanation:

P (Triangle or Square) :

  • Area of Triangle + Area of Square / Area of Rectangle
  • 1/2 x 3 x 4 (height is found by Pythagorean Theorem) + (3)² / 10 x 6
  • 6 + 9 / 60
  • 15/60
  • <u>0.25</u>

<u></u>

P (Not the square) :

  • Area of rectangle - Area of square / Area of rectangle
  • 60 - 9 / 60
  • 51/60
  • 17/20
  • <u>0.85</u>
5 0
2 years ago
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