Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
−3.666667, hope that helps.
Answer:
43 if you follow the steps of PEMDAS
Step-by-step explanation:
9x5=45. 8÷4=2. 45-2=43
Hope this helps!
Answer:
10.05 meters
Step-by-step explanation:
If the diameter is 3.2 meters, then the radius is 1.6 meters.
Use the circumference formula, C = 2
r, and solve for C
C = 2r
C = 2(1.6)
C = 3.2
C = 10.05
So, to the nearest hundredth of a meter, the circumference is 10.05 meters
