line s has a slope of -9/5. line t has a slope of 5/9. are line s and line t parallel or perpendicular
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Answer:
see below
Step-by-step explanation:
The function is written in vertex form. It has a negative vertical scale factor, so you know ...
- the vertex is (2, -4)
- the vertical scale factor is 1/2
- the parabola opens downward
Vertex form is ...
f(x) = a(x -h)^2 +k . . . . . . . . . . vertical scale factor "a", vertex (h, k)
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Since you know the vertex and scale factor, you can plot some points on the graph. I find it convenient to think in terms of units either side of the vertex. These are values of x that would make (x-2)^2 be 1^2, 2^2, 3^2, 4^2 and so on. The vertical scale factor of -1/2 tells you that the y-differences for these points will be -1/2, -4/2, -9/2, -16/2 from the vertex. Then we have ...
vertex: (2, -4)
1 unit either side of the vertex: (1, -4.5), (3, -4.5)
2 units either side of the vertex: (0, -6), (4, -6)
3 units either side of the vertex: (-1, -8.5), (5, -8.5)
4 units either side of the vertex: (-2, -12), (6, -12)
You can plot these points and draw a smooth curve through them. Or, you can let a graphing calculator do it. The result will be similar to that shown below.
Hello! Hope I can assist you.
Let us simplify some terms first!
From here, group like terms
Hope this helps!
Let us simplify some terms first!
From here, group like terms
Hope this helps!
