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Otrada [13]
2 years ago
12

line s has a slope of -9/5. line t has a slope of 5/9. are line s and line t parallel or perpendicular

Mathematics
1 answer:
uysha [10]2 years ago
5 0

Answer:

perpendicular

Step-by-step explanation:

If 2 lines are parallel then their slopes are equal

If 2 lines are perpendicular then the product of their slopes = - 1

Here

- \frac{9}{5} × \frac{5}{9} = - 1

Then the 2 lines are perpendicular

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Answer:

22-6y= 29

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-6y=7

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3 0
2 years ago
FINALS HELP SORRY!!!!!!
monitta
I believe the 4th one
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4 0
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Solve the compound inequality 6b < 42 or 4b + 12 > 8
swat32

Answer:

b<7

Step-by-step explanation:

6b<42

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b<7

3 0
3 years ago
Please help and show your work ( no links or files) plz
mr_godi [17]

Answer:

Step-by-step explanation:

Use the formula for the area of a triangle,

Area of a triangle = \frac{1}{2}(\text{Base})(\text{Height})

7). Area of the triangle = \frac{1}{2}(20)(7.4)

                                       = 74 km²

8). Area of the triangle = \frac{1}{2}(4)(15.4)

                                     = 30.8 cm²

9). Area of the triangle = \frac{1}{2}(16)(7)

                                      = 56 m²

10). Area of the triangle = \frac{1}{2}(11)(7.7)

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5 0
2 years ago
Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.
Reil [10]

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

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h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

8 0
3 years ago
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