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uranmaximum [27]
2 years ago
9

The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distr

ibution. Test vs when the sample has , , and with . Find the value of the standardized z-test statistic. Round your answer to two decimal places.
Mathematics
1 answer:
Tanya [424]2 years ago
4 0

Complete Question

The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Test H_o : p =  0.28 vs H a : p <  0.28when the sample has n 900 , and \^ p = 0.216 with SE=  0.01 . Find the value of the standardized z -test statistic. Round your answer to two decimal places.

Answer:

The value is  z =  -6.40

Step-by-step explanation:

Generally the standardized test statistics is mathematically represented as

     z =  \frac{\^ p  -  p }{ SE }

=>  z =  \frac{0.216  -  0.28 }{ 0.01  }

=>  z =  \frac{0.216  -  0.28 }{ 0.01  }

=>  z =  -6.40

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Step-by-step explanation:

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Can y’all help me please
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Answer:

w = 5

Step-by-step explanation:

The perimeter of a rectangle is given by

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Area = length x width
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3 years ago
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The expression f(x) = 12(1.035)* models the monthly growth of membership in the new drama club at a school. According to the fun
olga nikolaevna [1]

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

y=a(1+r)^{x}

Here,

<em>y</em> = final value

<em>a</em> = initial value

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<em>x</em> = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

f(x) = 12\cdot(1.035)^{x}

Comparing this function with the exponential growth function:

a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}

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Thus, the monthly growth rate is 3.5%.

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3 years ago
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