Answer:
The equation of line in the form of Ax + By = C is: 
Step-by-step explanation:
We need to find the equation of line, having slope m = -4 and passes through point (-2,-9)
First we need to find slope and y-intercept of the line.
The slope is given i.e. m = -4
Now, we need to find the y-intercept
Using the point (-2,-9) and slope m = -4, y-intercept can be found using:
Now, the equation of required line having slope m = -4 and y-intercept b = -17 is:
Now writing in form of Ax + By = C
So, the equation of line in the form of Ax + By = C is: .
Answer:
360 ft.
Step-by-step explanation:
Each base distance is 90 so since there are 4 bases you solve:
90*4 = 360
Answer:
Probability of no one picking up a defective product = 571 / 1540
Step-by-step explanation:
Total number of items = 22
non-defective items = 22-3 = 19
Probability of all three picking up non-defective products
= 19/22 * 18/21 * 17/20
= 969/1540
Probability of at least one picking up a defective product
= 1 - 969/1540
= 571/1540
(=0.371, approx.)
Answer:
d. 92.84
Step-by-step explanation:
The top edge overhangs the bottom edge by (39 -27)/2 = 6 ft on both ends. This makes the slant side have length
.. √((6 ft)^2 +(12 ft)^2) = 6√5 ft
Then the perimeter is
.. (39 +6√5 +27 +6√5) ft = 66 +12√5 ft
= 92.83 ft
Since there are two events happening simultaneously (windy and no sun), we can apply the concept of conditional probability here.
P(A|B) = P(A∩B)/P(B)
where it means that given B is happening, the probability that A is happening as well is the ratio of the chance for A and B to happen simultaneously over the chance of B to happen.
For our case, this can be interpreted as
P(A|B): it is the probability that it is windy (A) GIVEN that there is no sun (B)
P(A∩B) : chance of wind and no sun
P(B) : chance that there is no sun tomorrow
The chance of P(A∩B) is already given as 20% or 0.20. Since there is 10% or 0.10 chance of sun, then chances of having no sun tomorrow is (1-0.10) = 0.90.
Thus, we have P(A|B) = 0.2/0.9 ≈ 0.22 or 22%.
So, answer is B: 22%<span>.</span>
