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seropon [69]
3 years ago
6

How can you use the relationship between side lengths to determine when 3 lengths form a triangle

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

x+4=y+x

Step-by-step explanation:

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Which best explains why the equation 7x + 3 = 7x + 3 has infinitely many<br> solutions?
DochEvi [55]

Answer:

B

Step-by-step explanation:

both sides are equal to begin with so any x that you put in, will get multiplied by 7 and have 3 added to it

7 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
3 years ago
What is 15 times 7/5 compared to 15 equal?
Kaylis [27]

Answer:

I do not know

Step-by-step explanation:

4 0
3 years ago
IAnser this pleaseSnss
Goryan [66]

Answer:

Im pretty sure its x< 3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is an equation in point-slope form for the line that passes through the points (−3,5) and (2,−3)?
fredd [130]
(-3,5). (2,-3)
x1,y1. x2,y2

y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1

plug the rest in

4 0
3 years ago
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