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alina1380 [7]
2 years ago
7

I need helpppppppp!!!!

Mathematics
1 answer:
kati45 [8]2 years ago
8 0

What do you need help with?

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PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
m_a_m_a [10]

Answer:

d 20.4 years

Step-by-step explanation:

The equation is

A = Pe ^(rt)

We know that r = .034

We want the money to double  so A = 2P

Substitute in

2P = P e ^(.034t)

Divide by P

2P/P = P/P e ^(.034t)

2 = e^ (.034t)

Take the natural log on each side

ln (2) = ln(e^ (.034t))

ln (2) = .034t

Divide by .034

ln (2) /.034 = .034t/.034

ln (2)/.034 = t

20.3867 =t

4 0
3 years ago
Please answer I will give 20 and brainiest
Mariulka [41]

Answer:

Option 4

Step-by-step explanation:

Coordinances for a three-dimensional coordinate system are (x, y, z).

The letter labeling each axis is always on the positive side.

The fourth option is correct because you move 3 units away from the 'x', 1 unit away from the 'y', then 2 units toward the 'z'.

3 0
2 years ago
A gold, a silver, and a bronze medal are awarded in an Olympic event. In how many possible ways can the medals be awarded for a
RideAnS [48]

Answer:

720 possible ways

Step-by-step explanation:

The gold is awarded to the first position, the silver is awarded to the second position while the bronze is awarded to the third position.

The first position can be taken by any of the 10 runners

Now, the second position can be taken by remaining 9 runners

while the third position can be taken by the renaming 8 runners.

Thus, the number of ways in which these medals can be awarded = 10 * 9 * 8 = 720 ways

3 0
3 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
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