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Nostrana [21]
3 years ago
14

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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Determine the domain for the graphed function:<br> Please help meeee
Rom4ik [11]

Answer:

D

Step-by-step explanation:

First, domain refers to the x axis. So you would find the lowest number on the X axis, -2, and then you look at the kind of dot on that number. It is an open dot, which means that it is all the numbers up to -2, but does not include -2. Then you find the highest number, in this case 2. Looking at the dot that is marking it, it is a closed dot, meaning it includes the number 2. So the domain would be numbers between -2 and 2, but does not include -2. all numbers greater than -2, x, all numbers less than and equal to 2.

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3 years ago
What is the answer to this problem?
AURORKA [14]

The answer to the problem is x - 1

5 0
3 years ago
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Please solve the following complex number system ASAP, show work and please simplify fully.
Illusion [34]

Answer:

x= 16±√-64 over 2

Step-by-step explanation:

x= -(-16)±√(-16)²-4×1×80 over 2×1

x= 16±√256-320 over 2

x= 16±√-64 over 2

can also be represented with all real numbers.

7 0
3 years ago
A.) SSS<br><br> B.) AAS<br><br> C.) ASA<br><br> D.) SAS
Vlada [557]

Side BC is congruent to side BC.

Using the congruent angles and the angle bisectors, you can get two angles congruent to two other angles, so you use ASA to prove the triangles congruent. Then you use CPCTC to prove the sides congruent.

Answer: C.) ASA

7 0
3 years ago
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
3 years ago
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