Answer:
2.5 bottles or 3 bottles
Step-by-step explanation:
Given that :
Dimension of lot :
22.5 yds by 20.4 yds
Area of lot = 22.5 * 20.4 = 459 yd²
Volume per bottle of herbicide = 12 fl oz
1.1 fl oz combined with water treats an area of 155 ft²
Number of 1.1 fl oz from 12 fl oz that can be obtained : 12 / 1.1 = 10.90
1 yard² = 9 feet²
459 yard² = (459 * 9) = 4131 feet²
Number of 151 feet² that can be obtained from 4131 feet²
4131 feet² / 155 ft²
= 27.3576 times
= 27.3576 / 10.909
= 2.507
This means he'll have to buy a minimum of 3 bottles if a fraction of a bottle can't be purchased.
Answer:
Y = X times 0.28
Step-by-step explanation:
1. You set it up as a proportionality
12/1 and 3.36/x
The x stands for how much money it takes to get 1 ounce
2. You do the old man line.
12 times x = 3.36 times 1
12x = 3.36
3. Now you divide 3.36 by 12
3.36 divided by 12
.28
4. You insert 0.28 into the problem
12 times 0.28 = 3.36
X = 0.28
So 1 ounce costs $0.28
So Y = X times 0.28
<span>Draw a regular hexagon. Connect the center to each of the six vertices. Thus, you have six triangles, each with base 10.. The apothem is the height of each triangle. Then the area of each triangle is (1/2)(10)(12) = 60. You have six triangles so the aarea of the hexagon is 6*60 = 360.</span>
Answer:
16
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Leg <em>a</em> = <em>a</em>
Leg <em>b</em> = 12
Hypotenuse <em>c</em> = 20
<u>Step 2: Solve for </u><em><u>a</u></em>
- Substitute in variables [Pythagorean Theorem]: a² + 12² = 20²
- Evaluate exponents: a² + 144 = 400
- [Subtraction Property of Equality] Isolate <em>a</em> term: a² = 256
- [Equality Property] Square root both sides: a = 16
Answer:
Part a) The area of the swimming pool is 
Part b) The total area of the swimming pool and the playground is 
Step-by-step explanation:
Part a) Find the area of the swimming pool
we know that
The area of the swimming pool is

where
L is the length side
W is the width side
we have

substitute the values


therefore
The area of the swimming pool is 
Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground
we know that
To obtain the area of the playground multiply the area of the swimming pool by one and a half

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground
so

therefore
The total area of the swimming pool and the playground is 