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3 years ago

HELP ME ASAP PLS

Mathematics

1 answer:

Alla [95]3 years ago

6 0

The vertex point is (0,4)
The two other points are (-2,0)(2,0)

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In triangle ABC, c = 8, b = 6, and ∠C = 60°. sin∠B = _____

satela [25.4K]

Hello,

sin B/b=sin C/c
==>sin B=√3 / 2 * 6/8=3√3 /8

6 0

3 years ago

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Which of the following relations is a function?

MrMuchimi

Answer:

A. (1,4), (-5, 2), (7, 1), (-8, 2)

Step-by-step explanation:

Definition of a Function

A function is a relation between an input and an output set of values with the condition that every element in the input set relates only to one element in the output set.

From the four options presented in the question, we must select the only one that doesn't repeat the value for x and has a different value of y.

For example, the set

B. (1,4), (-5, 6), (1, 3), (-8, 2) is not a function because the input value of 1 has two different output values

C. (1,0), (-5,3), (7, 1), (-5,5) is not a function either because the input value of -5 has two different output values

The correct choice is:

A. (1,4), (-5, 2), (7, 1), (-8, 2)

6 0

2 years ago

Kay's Dessert Shop bakes cookies. The ratio of chocolate chip to sugar cookies baked is always 5 to 2. If she bakes 210 cookies

Gnom [1K]

Answer: 60

Step-by-step explanation:

Given

The ratio of chocolate chip to sugar cookies is 5:2

If she bakes 210 cookies in one day

Suppose she baked x amount of chocolate chips on that day

So, we can write

$\Rightarrow x=\dfrac{2}{5+2}\times 210\\\\\Rightarrow x=\dfrac{2}{7}\times 210=60$

There were 60 sugar cookies on that day

6 0

3 years ago

X^2+2y=19 X^2+y^2=34

Katen [24]

Answer:

x=3

y=5

Step-by-step explanation:

3×3=9

5×5=25

9+25=34

[3^2+5^2=34]

3^2=9

2×5=10

9+10=19

[3^2+2×5=19]

5 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

3 years ago

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