(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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The length of the rope needed is 15 feet
Given the following parameters;
- Height of the pole = 9 foot
- The distance from the <u>rope away from the base </u>of the pole is 12 feet
Required
To get the length of the rope, you will use the pythagoras theorem expressed as:
Substituting the given parameters:
c² = 9² + 12²
c² =81 + 144
c² = 225
c = √225
c = 15 feet
Therefore the length of the rope needed is 15 feet
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Answer: 336.80 miles, 
North of east
Step-by-step explanation:
Given
Plane lands at a point 324 miles east and 92 miles north
Distance is given by using Pythagoras theorem
Direction is given by using figure i.e.
Direction is North of east
You didn’t show a picture of the graph, although the equation would be y=-1/2x+2
so every two x spaces forward you should go down one y space and the y should start at 2 when x = 0
<span>= 48 - 18i + 8i - 3i</span>²<span>
= 48 – 10i – 3i</span>²
