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OLEGan [10]
3 years ago
9

A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 160 lbs and each b

ox of books weighs 50 lbs. The maximum capacity of the elevator is 1000 lbs. How many boxes of books can the delivery person bring up at one time? Note: The delivery person cannot bring up a partial/fraction of a box.
Mathematics
1 answer:
german3 years ago
8 0

Answer:

16 boxes

Step-by-step explanation:

160+50x=1000

Solve for the x and you'll get 16.8. Now, because you can't have a fraction of a box, and you can't go over the limit, the answer is 16 boxes.

(How to solve for x:

Get x by itself by subtracting 160 to both sides.

50x=1000-160

50x=840

Divide both sides by 50.

x=16.8)

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What is -2x + 3y = 15 in slope intercept form
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y=mx+b

-2x+3y=15

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3 years ago
Keisha is walking around a track that is 400 yards long. She has walked around the track 5 times so far. How many more yards doe
anyanavicka [17]
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3 0
3 years ago
A candy store sells bags of fruit-flavored candy for $2 and chocolate candy for $3. Jasmine spends $54 on candy for her friends.
34kurt

Answer:

2x + 3y = $54

Step-by-step explanation:

Standard Form ~ Ax + By = C

A and B in this case are just going to be numbers, they are just for substitution purposes.

Since x is fruit flavored candy and y is Chocolate, we can substituce the Fruit for A and Chocolate for B.

Now, we have 2x + 3y = C

The C is going to be the total cost. Therefore we have ~

2x + 3y = $54

Have a great day,

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8 0
3 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
3 years ago
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