All categories

3 years ago

What single decimal multiplier would you use to decrease by 7% followed by a 20% decrease

Mathematics

2 answers:

Vesna [10]3 years ago

6 0

Answer:

x 0.27

Step-by-step explanation:

if they are both decreasing then just add the two percentages together then divide by 100 to give you your decimal answer

AveGali [126]3 years ago

5 0

It would be 0.27 :)

Hope it helped hehe

You might be interested in

Find the endpoint P of a line segment whose midpoint Q lies at (5, -10) and whose other endpoint lies at (-8, -4). Write it as a

blondinia [14]

P is (18, -16)

to find the answer, u would solve it in reverse order of the midpoint formula by first doing the x-values:

5(2)= 10-(-8) = 18

and then the same to y-values:

-10(2)= (-20)-(-4) = -16

to get:

(18, -16)

8 0

3 years ago

How do you solve 32 - 6x = 53?

katrin2010 [14]

$\large\boxed{x=-\frac{7}{2}}$

To solve for $x$ , we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

$\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}$

Divide both sides of the equation by $-6$ .

$\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}$

7 0

2 years ago

Read 2 more answers

Paul's car will go 49 kilometers on 7 tanks. Paul wants to know how fuel efficient the car is. Please help by computing the rati

alisha [4.7K]

Answer:

7 : 1

Step-by-step explanation:

Paul's car goes 40 kilometers on 7 tanks.

Distance : Tanks

49 : 7

Fuel efficiency means the distance traveled by the car in one tank.

Therefore, we will reduce the ratio by dividing both sides by 7.

Distance : Tanks

$\frac{49}{7}$ : $\frac{7}{7}$

7 : 1

Therefore, car's fuel efficiency is 7 kilometers in one tank or the ratio between Distance traveled and fuel tanks is 7 : 1.

8 0

3 years ago

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2

5 0

3 years ago

Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form

Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = $\sqrt{16}$ = 4

4 0

3 years ago