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kozerog [31]
3 years ago
10

Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = \sqrt{16} = 4

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slava [35]
\sqrt{1-2b} = 1 + b \\ \\ 1 - 2b = (1 + b)^2 \\ \\ 1 - 2b = 1 + 2b + b^2 \\ \\ -2b = 2b + b^2 \\ \\ 2b + 2b + b^2 = 0 \\ \\ 4b + b^2 = 0 \\ \\ b(4 + b) = 0 \\ \\ b = 0, -4 \\ \\ b = -4 \ is \ false \\ \\ b = 0

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We gathered the solutions of b = 0, -4.
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