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2 years ago

How do you solve 32 - 6x = 53?

Mathematics

2 answers:

katrin2010 [14]2 years ago

7 0

$\large\boxed{x=-\frac{7}{2}}$

To solve for $x$ , we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

$\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}$

Divide both sides of the equation by $-6$ .

$\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}$

Cerrena [4.2K]2 years ago

3 0

Answer:

x = - 3.5

Step-by-step explanation:

32 - 6x = 53 ( subtract 32 from both sides )

- 6x = 21 ( divide both sides by - 6 )

x = $\frac{21}{-6}$ = - $\frac{7}{2}$ = - 3.5

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1. 4<7 Multiply both sides by 7, then by 6, then by 3, then by 10

erastova [34]

Answer:No, it didn't affect the inequality sign because we multiplied and divided by a negative number. In the 4th operation, the inequality sign changed because we divided by a negative number

Step-by-step explanation:

3 0

3 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$

Now we have everything in order to replace into formula (1):

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

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2 years ago

Find f(t – 3) for f(x) = 4x2 – 8x + 4.

GarryVolchara [31]

Answer:

4t^2 - 32t + 64.

Step-by-step explanation:

f(x) = 4x2 – 8x + 4

f(t - 3) = 4(t - 3)^2 - 8(t - 3) + 4

= 4(t^2 - 6t + 9) - 8t + 24 + 4

= 4t^2 - 24t + 36 - 8t + 28

= 4t^2 - 32t + 64.

5 0

2 years ago

Please help me if you can thank you. For question A the answer is 5000 brochures. My question is how did they get that answer?

Sophie [7]

Answer:

Step-by-step explanation:

Company A's equation is 900+0.50x5,000

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Both equal 3,400 and have to be multiplied by 5,000

8 0

2 years ago

Solve for a: a(a-3) =100

marissa [1.9K]

$a(a-3) =100\\
a^2-3a-100=0\\
\Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\
\sqrt{\Delta}=\sqr{409}\\
a_1=\dfrac{-(-3)-\sqrt{409}}{2\cdot1}=\dfrac{3-\sqrt{409}}{2}\\
a_2=\dfrac{-(-3)+\sqrt{409}}{2\cdot1}=\dfrac{3+\sqrt{409}}{2}$

5 0

3 years ago